Draw a diagram to illustrate the problem as shown below.
Let v = speed of the westbound car, mph
Because the eastbound car travels 4 mph faster than the westbound car, its speed is (v+4) mph.
After 2 hours,
the westbound car travels 2v miles west, and the eastbound car travels 2(v+4) miles east.
Because they become separated by 208 miles, therefore
2v + 2(v+4) = 208
4v + 8 = 208
4v = 200
v = 50 mph
The westbound car travels at 50 mph.
The eastbound car travels at v+4 = 54 mph
Answer: The eastbound car travels at 54 mph.
Answer:
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes
Step-by-step explanation:
We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 35 - 1 = 35
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.0322
The margin of error is:
M = T*s = 2.0322*30 = 60.97
The upper end of the interval is the sample mean added to M. So it is 204 + 60.97 = 264.97
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes
I don't know what you are asking but my best guess is it will be
$4.46 in total
{-2x-5y=13
<u>{2x-5y=17 </u>(+)
<em /> -2x+2x-5y-5y=13+17
-10y=30 /:(-10)
y=-3
2x-5y=17
2x-5*(-3)=17
2x+15=17
2x=2
x=1
<em>Solution: (1; -3)</em>
Answer:
x=2
Step-by-step explanation:
the slope is vertical meaning it is undefined.