For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
C is correct.
Step-by-step explanation:
Khan Academy said so.
Answer: adjoining HAVE A GREAT DAY
Answer:
by doing it the same way you did with the first one.
Step-by-step explanation:
Answer:
15cm
Step-by-step explanation:
scale factor =image diatace/object distance
0.75=x/20
0.75×20=x
15=x
: .x=15cm
