Answer:
A is correct < C and < C" are congruent after both the translation and the dilation.
Step-by-step explanation:
The shape of the triangle remains the same after the translation and the dilation. After the dilation the new triangle is bigger by a factor 2 but the shape ( and therefore the angles are equal. The 2 triangles are similar,
Answer:
-1.23 is the correct answer
Step-by-step explanation:
-0.3×4.1 = -1.23 because when multiplying the negative is given to the answer unless there are 2 negatives in which case they cancel out.
Answer:
The answer is below
Step-by-step explanation:
A polynominal function that describes an enclosure is v(x)=1500x-x2 where x is the length of the fence in feet what is the maximum area of the enclosure
Solution:
The maximum area of the enclosure is gotten when the differential with respect to x of the enclosure function is equal to zero. That is:
V'(x) = 0
V(x) = x(1500 - x) = length * breadth.
This means the enclosure has a length of x and a width of 1500 - x
Given that:
v(x)=1500x-x². Hence:
V'(x) = 1500 -2x
V'(x) = 0
1500 -2x = 0
2x = 1500
x = 1500 / 2
x = 750 feet
The maximum area = 1500(750) - 750² = 562500
The maximum area = 562500 feet²
The correct answer is C. The form for shifts is (x-h)^2 +k where h=the x variable ( horizontal shift left or right) and k = the y variable (vertical shift up or down) The confusing part for many students is remember that if you are moving left it's subtraction So in the form x-h it is actually x - (-h) so it gets turned into a positive/ addition sign.
Answer:
Height equation for first student is correct while that of second student is incorrect.
Step-by-step explanation:
Given that the function of height should be quadratic function.
Standard form of Quadratic function is given as,
.
Degree of quadratic function is 2.
Equation of height for first student is given as 
Since, above equation has degree 2 and equation is in quadratic form with value of b and c as 0.
Therefore, height equation for first student is correct.
Equation of height for second student is given as 
.
Since the degree of above equation is 1, hence it cannot be the quadratic function. Hence second equation is not an quadratic function.
Therefore, height equation for second student is incorrect.
