9/27, 12/27, 16/27
So this is a geometric sequence as each term is 4/3 the previous term.
Since the common ration is greater than one the sum of the series diverges, it does not exist. (The sum just keeps getting larger and larger)
For a geometric series to have a sum r^2<1
So that the normal sum....
s(n)=a(1-r^n)/(1-r) becomes if r^2<1
s=a/(1-r)
It would be 2.31 i think.. If not i apologize.
Answer:
K'= (-2, 4)
Step-by-step explanation:
First we are going to rotate our point 270° counterclockwise.
The rule for a 270° counterclockwise rotation is 
, which means that we just need to interchange the coordinates of the point and change the sign of the x-coordinate:
Now, to shift the point 3 units down, we just need to subtract 3 units from the new y-coordinate of our resulting point form the previous procedure:
We can conclude that the coordinates of K' are (-2, 4)
-1/3+6
17/3
(Mark me the brainliest if this was helpful)
We would multiply $30 by 5% to first find 5%
5% = 0.05
$30 x 0.05 = $1.50
Now we add that to 30
$30 + $1.50 = $31.50
Your answer is $31.50
