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faust18 [17]
1 year ago
13

Hurrrry helpppp show your work

Mathematics
1 answer:
Nostrana [21]1 year ago
6 0

Answer: 17

Step-by-step explanation:

substitute -3 for a and -5 for b. the equation will be\frac{(-3)^{2}+(-5)^{2}  }{-3-(-5)}. then when you simplify, you will get \frac{9+25}{-3+5}. finally, add and you will get \frac{34}{2} which is 17.

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The graph of g(x) = -x^2 is shifted 3 units left and 1 unit up. If this new graph is f(x), then what is the value of f(-1.5)
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\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
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\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
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\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
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\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see.

to the left by 3 units, C = +3
up by 1  unit, D = 1

\bf g(x)=-x^2\\\\\\ g(x)=-1(1x+\stackrel{C}{0})^2+\stackrel{D}{0}\implies g(x)=-1(1x+3)^2+1
\\\\\\
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and surely you know how much that is.
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