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Kipish [7]
3 years ago
9

An observer (O) is located 900 feet from a building (B). The observer notices a helicopter (H) flying at a 49° angle of elevatio

n from his line of sight. How high is the helicopter flying over the building? You must show all work and calculations to receive full credit.

Mathematics
1 answer:
Firdavs [7]3 years ago
6 0

Answer:

1035.33 feet

Step-by-step explanation:

h=900tan49

=1035.33 feet

I hope it helps

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Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1
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Let's rewrite the left side keeping in mind the next propierties:

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log(x*y)=log(x)+log(y)

Therefore:

log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1

Now, cancel logarithms by taking exp of both sides:

e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e

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Substract 16e-8ex+ex^{2} from both sides and factoring:

-(x-4)*(-8-4e-2x+ex)=0

Multiply both sides by -1:

(x-4)*(-8-4e-2x+ex)=0

Split into two equations:

x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0

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Add 4 to both sides:

x=4

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x(e-2)=4e+8

Divide both sides by e-2:

x=\frac{4*(2+e)}{e-2}

The solutions are:

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If we evaluate x=4 in the original equation:

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This is an absurd because log (x) is undefined for x\leq 0

If we evaluate x=\frac{4*(2+e)}{e-2} in the original equation:

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Which is correct, therefore the solution is:

x=\frac{4*(2+e)}{e-2}

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