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katovenus [111]
3 years ago
8

What is the greatest common factor of 32,24,40

Mathematics
1 answer:
Mandarinka [93]3 years ago
8 0

The GCF of 24, 32, and 80 must be 8, since it is the largest number common to both lists. Example 1 Find the greatest common factor of each set of numbers by listing factors.
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Mindy lives of a mile away from school. Ron lives as far from school as Mindy. How far is Ron's house from school?
jek_recluse [69]

Answer:

additive comparison

Step-by-step explanation:

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Answer : 7.5 inches
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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
Tresset [83]

Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

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Answer:

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Step-by-step explanation:

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A volcano on a recently discovered planet rises to a height of 16.871 mi.
Vinvika [58]
The answer is 89078.88 ft

1 mile = 5280 feet

Multiply 16.871 by the length value of 5280

16.871 * 5280 = 89078.88 ft
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