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irga5000 [103]
1 year ago
14

Question in image ddddddddddddddddd

Mathematics
1 answer:
Kisachek [45]1 year ago
3 0

Step-by-step explanation:

"congruent" for lines simply means they are equally long.

15. yes. AB = EF = 3

16. yes. BD = DF = 8

17. no. AC = 5, CD = 6

18. yes. AC = DE = 5

19. no. BE = 13, CF = 14

20. no. CD = 6, DF = 8

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If you good at math help please!
olchik [2.2K]

Answer:

3 because your domain should not repeat

5 0
3 years ago
Read 2 more answers
Find the x- and y- intercepts of the line with the given equation <br><br> -6x+8y=-36
Likurg_2 [28]

Answer:

Y int at

(

0

,

3

2

)

X int at

(

3

,

0

)

Step-by-step explanation:

The line is easier to visualize when the equation is in slope-intercept form:

4

x

+

8

y

=

12

Divide each side by 4:

x

+

2

y

=

3

2

y

=

−

x

+

3

y

=

−

1

2

x

+

3

2

Y-intercept (plug in 0 for x):

y

=

−

1

2

(

0

)

+

3

2

y

=

3

2

X-intercept (plug in 0 for y):

0

=

−

1

2

x

+

3

2

−

3

2

=

−

1

2

x

x

=

3

5 0
3 years ago
Read 2 more answers
For what value of a does<br> (9) ***<br> = 3438-1<br> -1<br> 0<br> 1<br> no solution
mario62 [17]

Answer:

<h2>0</h2>

solution,

(\frac{1}{7} ) ^{3a + 3}  =  {343}^{a - 1}  \\ or \: ( {7}^{ - 1} ) ^{3a + 3}  =  {(7}^{3} ) ^{a - 1}  \\ or \: (7) ^{ - 3a - 3}  =  {(7)}^{3a - 3}  \\ or \:  - 3a - 3 = 3a - 33 \\ or \:  - 3a - 3a =  - 3 + 3 \\ or \:  - 6a =  0 \\  \: a = 0

hope this helps..

Good luck on your assignment..

3 0
4 years ago
What is the expression in factored form?
fredd [130]
9x² - 12x + 4

write the equation with two middle terms that multiply to give 36
9x² - 6x - 6x + 4

by factorisation
3x(3x - 2) - 2(3x - 2)

(3x - 2)²

Thus OPTION A
4 0
3 years ago
Solve for y
Andreas93 [3]

Answer:

y = 3

Step-by-step explanation:

2y - 3 = \sqrt{3y^2-10y+12}

square both sides to remove sqrt bracket

(2y - 3)^2 = ( \sqrt{3y^2-10y+12} )^2

simplify both sides

(2y - 3)(2y - 3) = 3y^2 - 10y + 12

4y^2 - 12y + 9 = 3y^2 - 10y + 12

bring all value to left side

y^2 - 2y - 3 = 0

factor

(y - 3)(y + 1)

solve for y

y = 3, y = -1

When plugged back into the equation, only y = 3 is true

8 0
3 years ago
Read 2 more answers
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