= 1/2kx2
U = potential energy of a spring at a certain position
k = the spring constant, specific to the spring, with units N/m.
x = distance the spring is stretched or compressed away from equilibrium
Potential Energy: Elastic Formula Questions:
1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?
Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:
U = 1/2kx2
U = 1/2(7.50 N/m)(0.40 m)2
U = 0.60 N∙m
U = 0.60 J
Answer:
X=20
Step-by-step explanation:
The surface area is the prism is 108mm2.
8 green apples
11 red apples
5 nectarines
12 oranges = 36 total fruits
P(green apple then nectarine)
8/36 x 5/36 = 4/18 x 5/36 = 2/9 x 5/36 = 10/324 = <u>5/162</u>
<u></u>
P (two oranges)
12/36 x 12/36 = 1/3 x 1/3 =<u> 1/9</u>
The answer to this question is 2
