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3 years ago

4,320 is divisible by? 3 9 10

Mathematics

2 answers:

worty [1.4K]3 years ago

7 0

The answer is

3,9 and 10

marusya05 [52]3 years ago

5 0

Answer:

3, 9, and 10

Step-by-step explanation:

To figure out whether 4,320 is divisible by these numbers, we can use their <em>divisibility rules</em> to help us out.

A number is divisible by 3 or 9 if its digits add up to a number divisible by 3 or 9. The digits of 4,320 add to 4 + 3 + 2 + 0 = 9, which is divisible by both 3 and 9, so <em>4,320 is divisible by 3 and 9</em>.

A number is divisible by 10 if its last digit is a 0, which we have here, so <em>4,320 is divisible by 10</em>.

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3 years ago

Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$

Anna [14]

Answer:

$\large\boxed{1\dfrac{1}{3}\ u^2}$

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

$x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1$

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

$\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}$

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3 years ago

Need hello fast I don’t know what to do

Free_Kalibri [48]

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3 years ago

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puteri [66]

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3 years ago

The Bayer family just left the local pet store with Rover, their new family dog. The pet store owner told the Bayer family that

anyanavicka [17]

Answer:

A. Complete table below

B. Graph is attached below

C. y = 7x - 10

D. 60 pounds.

Step-by-step explanation:

We are given that, Bayer would grow at an average rate of 7 pounds per month.

So, in order to complete the table, <em>we will add 7 to the weights column</em>.

Part A: Thus, we get the following table.

Age, in months 2, 3, 4, 5, 6, 7, 8

Weight, in pounds 4, 11, 18, 25, 32, 39, 46.

Part B: Since, we have the ordered pairs (x,y) given by,

(2,4), (3,11), (4,18), (5,25), (6,32), (7,39) and (8,46).

The graph is shown below.

Part C: Taking any two pairs say (2,4) and (3,11).

We get the slope is, $\frac{11-4}{3-2}$ i.e. slope is 7.

Then, y = mx + b gives, 4 = 7×2 + b i.e. b = 4-14 i.e. b = -10.

Hence, the linear model is given by 'y=7x-10', where x is the age(in months) and y is the weight(in pounds).

Part D: Now, we want to find the weight when Bayer is one year old.

Since, we have that, Bayer is already two months old.

So, we need to find weight when Bayer is 10 months old.

i.e. y=7x-10 ⇒ y = 7×10-10 ⇒ y = 70-10 ⇒ y=60

Hence, Bayer will be 60 pounds when he is one year orld.

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3 years ago