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3 years ago

12

Help Please! I'll Give Brainliest!

1 answer:

igor_vitrenko [27]3 years ago

5 0

Answer:

A

Step-by-step explanation:

the answer is a

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85,985 rounded to the nearest ten thousand.

miss Akunina [59]

Answer:

90,000

Step-by-step explanation:

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2 years ago

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A race car driver's goal is to complete a 1000-kilometer auto race in 4 hours or less. The driver's average speed is 4200 meters

Alexeev081 [22]

Yes the driver will meet their goal

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3 years ago

Write the radical expression in exponential form. <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%5Csqrt%5B2%5D%7B

Len [333]

1/x = x^-1
sqrt(x) = x^(1\2)

Therefore, answer is:

x^(-1/2)

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3 years ago

As reported in Trends in Television, the proportion of US households who have at least one VCR is 0.535. If 14 households are se

motikmotik

Using the binomial distribution, it is found that there is a 0.5601 = 56.01% probability that the number having at least one VCR is no more than 8 but at least 6.00.

For each household, there are only two possible outcomes. Either it has at least one VCR, or it does not. The probability of a household having at least one VCR is independent of any other household, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

14 households, hence $n = 14$ .
0.535 probability of having at least one VCR, hence $p = 0.535$ .

The probability of <u>at least 6 and no more than 8</u> is:

$P(6 \leq X \leq 8) = P(X = 6) + P(X = 7) + P(X = 8)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{14,6}.(0.535)^{6}.(0.465)^{8} = 0.1539$

$P(X = 7) = C_{14,7}.(0.535)^{7}.(0.465)^{7} = 0.2024$

$P(X = 8) = C_{14,8}.(0.535)^{8}.(0.465)^{6} = 0.2038$

Then:

$P(6 \leq X \leq 8) = P(X = 6) + P(X = 7) + P(X = 8) = 0.1539 + 0.2024 + 0.2038 = 0.5601$

0.5601 = 56.01% probability that the number having at least one VCR is no more than 8 but at least 6.00.

A similar problem is given at brainly.com/question/24863377

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2 years ago

3(y+7)-5y<br><br><br><br> Please limited time ♥️

Fynjy0 [20]

Answer: −2y+21

Step-by-step explanation:

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3 years ago

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