Can someone help me,it would be appreciated.Thanks!!! :D

Mathematics

1 answer:

Ierofanga [76]1 year ago

7 0

The number of pieces of 1/3 foot tall to make a 6 feet skyscraper is 18 pieces.

The model of a skyscraper comes in pieces and each piece is 1/3 feet tall.

After all the pieces are put together the skyscraper is 6 feet tall.

We have to calculate how many pieces were put together to make the 6 feet skyscraper.

Let X be the number of pieces put together to make a 6 feet skyscraper.

Now,

Each piece = 1/3 feet tall.

Since all the pieces together make 6 feet tall, we can write the number of pieces needed to make 6 feet tall as:

X x (1/3) = 6

X = 6 x 3 = 18

Thus, we need 18 pieces of 1/3 foot tall to make a 6 feet skyscraper.

Learn more about multiplication word problems here:

brainly.com/question/4686237

#SPJ1

You might be interested in

To find the area of a triangle, you can use the expression b × h ÷ 2, where b is the base of the triangle and h is its height. W

Stella [2.4K]

This is what u got: 2•8=16/2=8

4 0

3 years ago

Read 2 more answers

What is the Radius of a cylindrical water tank that has a circumference of 85 meters?

Tju [1.3M]

C=2pr

r=C/(2p) and we are given C=85 so

r=85/(2p) meters

r≈13.53 meters (to nearest one-hundredth of a meter)

7 0

3 years ago

Read 2 more answers

Law of sines?? side c=22 side a=16 side b= 21 solve for angle c??? help

den301095 [7]

Answer:

Angle C measures: $71.52^o$

Step-by-step explanation:

When you know the length of the three sides of the triangle and not a single angle, the law of sines is of no use. You need to use the law of cosines. In your case, since you want to find angle "C", you use the following;

$c^2=a^2+b^2-2\,a\,b\,cos(C)\\2\,a\,b\,cos(C)=a^2+b^2-c^2\\cos(C)=\frac{a^2+b^2-c^2}{2\,a\,b} \\cos(C)=\frac{16^2+21^2-22^2}{2\,(16)\,(21)}\\cos(C)=0.3169643\\C=arccos(0.3169643)\\C=71.52^o$