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mr_godi [17]
1 year ago
6

What alternative best describe the language represented by the following regular expression? Group of answer choices Strings do

not have 2 consecutive 0s. Strings that only start with 1. Strings do not have 2 consecutive 1s. Strings that consist of alternating 0s and 1s.
Mathematics
1 answer:
stira [4]1 year ago
8 0

An alternative that best describes the language represented by the following regular expression is (A) strings do not have 2 consecutive 0s.

<h3>What is a regular expression?</h3>
  • A regular expression (abbreviated regex or regexp; sometimes known as a rational expression) is a string of letters that indicates a search pattern in the text.
  • String-searching algorithms typically use such patterns for "find" or "find and replace" operations on strings, as well as input validation.
  • In theoretical computer science and formal language theory, regular expression techniques are developed.
  • As an example: Strings do not have two consecutive 0s, which is an alternative that best describes the language represented by the following regular expression (0∪ε)(1∪10).

Therefore, an alternative that best describes the language represented by the following regular expression is (A) strings do not have 2 consecutive 0s.

Know more about regular expressions here:

brainly.com/question/14085053

#SPJ4

The complete question is given below:

What alternative best describes the language represented by the following regular expression?

(0∪ε)(1∪10)

Group of answer choices

(A) Strings do not have 2 consecutive 0s.

(B) Strings that only start with 1.

(C) Strings do not have 2 consecutive 1s.

(D) Strings that consist of alternating 0s and 1s.

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B)  Product A

Step-by-step explanation:

<u>Exponential Function</u>

General form of an exponential function: y=ab^x

where:

  • a is the initial value (y-intercept)
  • b is the base (growth/decay factor) in decimal form
  • x is the independent variable
  • y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

<u>Part A</u>

<u>Product A</u>

Assuming the function for Product A is <u>exponential</u>:

f(x) = 0.69(1.03)^x

The base (b) is 1.03.  As b > 1 then it is an <u>increasing function</u>.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, <u>product A is increasing by 3% each year.</u>

<u>Part B</u>

\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%

Check using different two consecutive values of f(t):

\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%

Therefore, as 3% > 1%, <u>Product A recorded a greater percentage change</u> in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

  • a = 10,100
  • b = 1.01
  • n = t - 1 (as the initial value is for t = 1 not t = 0)

\implies f(t) = 10100(1.01)^{t-1}

To check this, substitute the values of t for 1 through 4 into the found function:

\implies f(1) = 10100(1.01)^{1-1}=10100

\implies f(2) = 10100(1.01)^{2-1}=10201

\implies f(3) = 10100(1.01)^{3-1}=10303.01

\implies f(4) = 10100(1.01)^{4-1}=10406.04

As these values match the values in the given table, this confirms that the found function for Product B is correct and that <u>Product B increases by 1% per year.</u>

4 0
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