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faltersainse [42]
1 year ago
10

What is the last digit of the product of all the numbers between 11 and 29?

Mathematics
1 answer:
tekilochka [14]1 year ago
5 0

we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.

<h3>What is the last digit of the product of all the numbers between 11 and 29?</h3>

Here we want to find the last digit of the product between all the whole numbers larger than 11 and smaller than 29.

Then we have the product:

P = 12*13*14*15*16*17*18*19*20*21*22*23*24*25*26*27*28

Now, notice that there is a 20 there.

Any number times 20 will end with a zero, then:

P = 20*(12*13*14*15*16*17*18*19*21*22*23*24*25*26*27*28)

Only with that, we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.

If you want to learn more about products:

brainly.com/question/10873737

#SPJ1

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Since y is never negative, this means the inverse x = sqrt(y) has the right hand side never be negative. The entire curve of sqrt(x) is above the x axis except for the x intercept of course. Put another way, we cannot plug in a negative input into the square root function for this reason. This similar idea applies to any even index such as fourth roots or sixth roots.

Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.

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3 years ago
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Tju [1.3M]
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3 years ago
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slope: 1/2

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Step-by-step explanation:

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