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jasenka [17]
3 years ago
13

Dylan works 30 hours a week. His hours are decreased by 20%. How many hours does he now work each week?

Mathematics
2 answers:
Vladimir79 [104]3 years ago
7 0

Answer:

He now work 24 hours each week

Step-by-step explanation:

Dylan works 30 hours a week. His hours are decreased by 20%.

The number of work hours 30 is decreased by 20%

we need to find 20% of 30

30 \cdot \frac{20}{100} =6

So number of hours should be decreased by 6

30-6= 24

he now work 24 hours each week

12345 [234]3 years ago
3 0
20% of 30 is 6. 30-6 is 24. He now works for 24 hours! Please mark brainliest!!!
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I’ll give u brainliest please help asap
Alchen [17]

Answer:

c, 14

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What are the correct answers? ​
VikaD [51]
7 12468643346777433578
3 0
2 years ago
HELP RIGHT AWAY ASAP PLEASE!!!
Mumz [18]

Answer:

when I worked it out I actually got -1466...

Step-by-step explanation:

Using order of operations you would multiply the 2 by 742, then subtract from left to right. 2 x 742 =1484 and 30 minus that is -1454. Subtracting 12 would give you -1466. I know that's not in the answer choices but that's what I got...

7 0
3 years ago
What is the first step in solving In(x - 1) = In6 - Inx for x?
kobusy [5.1K]

Answer:

x=3

Step-by-step explanation:

In(x-1) = In(6) - In(x)

In(x-1) + In(x) = In(6)

In((x-1)x) = In(6)

In(x^2-x) = In(6)

x^2-x=6

x^2-x-6=0

x^2+2x-3x-6=0

x(x+2)-3(x+2)=0

(x-3)(x+2)=0

x=3 because x=-2 need to be cancel out

8 0
2 years ago
NEED HELP I WILL MARK BRAINLIEST PLZ HELP
iris [78.8K]
First. Let’s find the radius. The diameter of the circle is 6in. Radius equals to half of the diameter. That means r=6/2=3in
Now if we find the area of circle, we have to multiply the quadratic of the radius by pi.
A=(3in)^2*3.14=9*3.14=28.26in^2
Now we can find the volume by multiply the area and the height.
V=28.26*8=226.08in^3
Now if we find the cube volume
V=a*b*h=15*9*9=1215in^3
V(toral)=226.08+1215=1441.08in^3
I hope this helped :)
5 0
3 years ago
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