Question

8x+4y=76x-8y=41 using ELIMINATION METHOD ​

Answer 1

Answer:

($\frac{5}{2}$ , - $\frac{13}{4}$ )

Step-by-step explanation:

8x + 4y = 7 → (1)

6x - 8y = 41 → (2)

multiplying (1) by 2 and adding to (2) will eliminate y

16x + 8y = 14 → (3)

add (2) and (3) term by term to eliminate y

22x + 0 = 55

22x = 55 ( divide both sides by 22 )

x = $\frac{55}{22}$ = $\frac{5}{2}$

substitute this value into either of the 2 equations and solve for y

substituting into (1)

8($\frac{5}{2}$ ) + 4y = 7

20 + 4y = 7 ( subtract 20 from both sides )

4y = - 13 ( divide both sides by 4 )

y = - $\frac{13}{4}$

solution is ( $\frac{5}{2}$ , - $\frac{13}{4}$ )