Ask question

Ask question

All categories

3 years ago

10

During a two-hour period, the temperature in a city dropped from a high of 51°F to a low of −11°F. What was the range of the tem

peratures during this period?

1 answer:

Likurg_2 [28]3 years ago

6 0

you have to take 51 plus 11 and add it up. then your answer should be 62 degrees different.

You might be interested in

Billy left home at 9 a.M. And rode his bicycle to the park at an average speed of 10 miles per hour here I got the park at 9:30

tamaranim1 [39]

Answer:

Park is <u>5 miles</u> from Billy's home.

Step-by-step explanation:

Given:

Billy left home at 9 a.m. And rode his bicycle to the park at an average speed of 10 miles per hour here and got the park at 9:30 a.m.

Now, to find the distance from park to Billy,s home.

Time it took Billy to rode his bicycle from park to home is from 9.30 a.m to 9.30 p.m.

So, the time = (9.30 - 9.00) = 30 minutes

$=\frac{30}{60}$ $=0.5\ hour.$

Speed = 10 miles per hour.

Now, to get the distance from park to Billy's home we put formula:

$Distance=Speed\times Time.$

$Distance=10\times 0.5$

$Distance=5\ miles.$

Therefore, park is 5 miles from Billy's home.

3 0

3 years ago

ILL GIVE U BRAINLYIST IF U GET IT RIGHT

yawa3891 [41]

Answer:

34

Step-by-step explanation:

5 0

3 years ago

A random sample of 169 observations is to be drawn from a population with a mean of 80 and a standard deviation of 39. find the

Drupady [299]

Mu=80, sigma=39, X=85
Z=(X-mu)/sigma = 5/39=0.128=0.13
P(X<=85)= 0.5517 (from Z-table)
so, P(X>85)=1-0.5517=0.4483 approx. thats 44.8% probability.

8 0

3 years ago

What is the best result for h?

Kryger [21]

Answer: First option.

Step-by-step explanation:

To solve for "h" from the given the equation $S=2\pi rh+2\pi r^2$ , you need to:

Apply the Subtraction property of equality and subtract $2\pi r^2$ to both sides of the equation.

Then you need to apply the Division property of equality and divide both sides of the equation by $2\pi r$ .

Then:

$S-2\pi r^2=2\pi rh+2\pi r^2-2\pi r^2\\\\S-2\pi r^2=2\pi rh\\\\\frac{S}{2\pi r}-\frac{2\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r}\\\\\frac{S}{2\pi r}-r=h$

6 0

3 years ago

Read 2 more answers

Help an someone help

lianna [129]

It’s blurry I can barely see it.

8 0

2 years ago

Read 2 more answers