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zaharov [31]
3 years ago
5

Answer the question below.

Mathematics
1 answer:
gregori [183]3 years ago
4 0

Answer:

1/3

Step-by-step explanation:

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Tom went on a bike to the store 3 miles away. If it took Tom 1/2 of an hour to get there and 2/3 of an hour to get back , what w
anastassius [24]

Answer:

5.14 mi/h

Step-by-step explanation:

To find the average speed, we simply find the total distance traveled by Tom and divide that by the total time the entire journey took him.

Average speed = (total distance traveled) / (total time taken)

TOTAL DISTANCE TRAVELED

He traveled 3 miles to and 3 miles fro. Hence:

3 + 3 = 6 miles

TOTAL TIME TAKEN

He spent ½ hr to go and ⅔ hr to return back. Hence:

½ + ⅔ = 7/6 hr

Therefore, the average speed is:

v = 6 / (7/6)

v = 36 / 7 = 5.14 mi/h

Tom's average speed was 5.14 mi/h.

8 0
3 years ago
Which of the following is the equation for the graph shown?
Allushta [10]
It would probably be the second option.

3 0
2 years ago
What is the solution of the inequality 9 - x^2<0?
Dmitry_Shevchenko [17]

Answer:

x < -3\quad \mathrm{or}\quad \:x > 3

Step-by-step explanation:

Given:

9-x^2 < \:0

Solve:

\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}

9-x^2-9 < 0-9

\mathrm{Simplify}

-x^2 < -9

Multiply\:both\:sides\:by\:-1\:

\left(-x^2\right)\left(-1\right) > \left(-9\right)\left(-1\right)

\mathrm{Simplify}

x^2 > 9

\mathrm{For\:}u^n\: > \:a\mathrm{,\:if\:}n\:\mathrm{is\:even}\mathrm{\:then\:}u\: < \:-\sqrt[n]{a}\:or\:u\: > \:\sqrt[n]{a}

x < -\sqrt{9}\quad \mathrm{or}\quad \:x > \sqrt{9}

\sqrt{9}=3

x < -3\quad \mathrm{or}\quad \:x > 3

<u><em>~lenvy~</em></u>

5 0
2 years ago
When solving 8 (x + 35) = -7, what is the correct sequence of operations? (5 points)
anzhelika [568]

Answer:

280 is your answer right answer

8 0
3 years ago
Write the equation 
Shkiper50 [21]
a)\ the\ slope-intercept\ form:\ y=mx+b\\--------------------------\\m=\frac{2}{3}\Rightarrow y=\frac{2}{3}x+b\\\\the\ point\ (-3;\ 6)\Rightarrow \frac{2}{3}\times(-3)+b=6\\\\-2+b=6\ \ \ \ \ |add\ 2\ to\ both\ sides\\\\b=8\\\\\boxed{y=\frac{2}{3}x+8}


b)\ the\ two-points\ formula:y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\-----------------------------\\the\ points:\ (3;-1);\ (5;\ 7)\\\\y-(-1)=\frac{7-(-1)}{5-3}(x-3)\\\\y+1=\frac{7+1}{2}(x-3)\\\\y+1=\frac{8}{2}(x-3)\\\\y+1=4(x-3)\\\\y+1=4x-12\ \ \ \ \ |subtract\ 1\ from\ both\ sides\\\\\boxed{y=4x-13}

3 0
3 years ago
Read 2 more answers
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