Answer the question below.
1 answer:
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Answer:
1,968
Step-by-step explanation:
Let x₁ and x₂, y₁ and y₂, and z₁ and z₂ represent the 3 pairs of siblings, and let;
Set X represent the set where the siblings x₁ and x₂ sit together
Set Y represent the set where the siblings y₁ and y₂ sit together
Set Z represent the set where the siblings z₁ and z₂ sit together
We have;
Where the three siblings don't sit together given as ∩
∩
By set theory, we have;
=
=
=
Therefore;
Where;
= The number of ways the 3 pairs of siblings can sit on the 7 chairs = 7!
= The number of ways x₁ and x₂ can sit together on the 7 chairs = 2 × 6!
= The number of ways y₁ and y₂ can sit together on the 7 chairs = 2 × 6!
= The number of ways z₁ and z₂ can sit together on the 7 chairs = 2 × 6!
= The number of ways x₁ and x₂ and y₁ and y₂ can sit together on the 7 chairs = 2 × 2 × 5!
= The number of ways x₁ and x₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 5!
= The number of ways y₁ and y₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 5!
= The number of ways x₁ and x₂, y₁ and y₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 2 × 4!
Therefore, we get;
= 7! - (2×6! + 2×6! + 2×6! - 2 × 2 × 5! - 2 × 2 × 5! - 2 × 2 × 5! + 2 × 2 × 2 × 4!)
= 5,040 - 3072 = 1,968
The number of ways where the three siblings don't sit together given as = 1,968
Answer:
Step-by-step explanation:
x^-y=1/(x^y) so 3t^-4=3/(t^4)