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vivado [14]
3 years ago
10

Use the quadratic formula to determine the exact solutions to the equation 6x^2 + 4x - 3 = 0

Mathematics
1 answer:
mezya [45]3 years ago
5 0
To solve quadratics, the most correct and effective way, in my opinion, is the quadratic formula:

{\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}.}<span><span>

Plugging it in, we get:

</span></span>\frac{-4\pm \sqrt{16+72} }{12}  =  \frac{-4\pm 2\sqrt{22}}{12} =  \frac{-2\pm \sqrt{22} }{6}

So the final answer is:

\frac{ \sqrt{22}-2 }{6} and \frac{-2- \sqrt{22} }{6}
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What is y=-4/3x +6. y=2
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The given equation is:
[/tex]y=-\frac{4}{3}x+6 [/tex] and we need to evaluate this for y=2.
So, first step is to plug in 2 for y in the above equation. Therefore,

2=-\frac{4}{3} x+6
2*3=-\frac{4}{3} x*3+6*3 Multiply each sides by common denominator 3
6=-4x+18
6-18= -4x Subtract 18 from each sides.
-12=-4x
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So, x=3

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Step-by-step explanation:

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givi [52]

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Read 2 more answers
-2 ×^2 - 4y +6. x=-3. y=-2 <br> evaluate ​
gladu [14]

Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<em><u>-2 ×^2 - 4y +6</u></em>

<em><u>Evaluate simply means to form an idea of something</u></em>

<em><u>So Evaluate for x=−3,y=−2</u></em>

<em><u>−2(−3)2−(4)(−2)+6</u></em>

<em><u>−2(−3)2−(4)(−2)+6</u></em>

<em><u>Answer =−4</u></em>

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How do you solve common core math when it asks you to write the first step question and answer?
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