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3 years ago

Please answer the question I would appreciate the help,please do it ASAP(as soon as possible) because i need the answer now.

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

3 0

Answer: I got 0.5 gallons which is also 1/2

Step-by-step explanation: Total tress there is 10 i got this by doing total amount of sap i started with the equation 3* (1/4) + 2* (3/8) + 4* (5/8) + 1* (1)and i worked my way down from there. Anyways after working this all out you would get 0.5 gallons for each tree

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13. Basil Tomlin's online checking account had a balance of $371.07. The balance did not

poizon [28]

Answer:

Step-by-step explanation

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3 years ago

Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting

stealth61 [152]

Answer:

Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$ and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

Thus, Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

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3 years ago

Read 2 more answers

Help with the CORRECT answer pretty please

lilavasa [31]

The answer would be (3,-1)

7 0

4 years ago

Read 2 more answers

X + y = -15<br> rewrite in y=mx+b

diamong [38]

Answer:

y = -x - 15

Step-by-step explanation:

x + y = -15

-x -x

y = -x - 15

5 0

3 years ago

The large piston in a hydraulic lift has an area of 2m^2. What force must be applied to the small piston with an area of .2m^2 i

Helen [10]

Answer:

147,000N

Step-by-step explanation:

A1= 2m^2

A2= 0.2m^2

F2= 14,700N

Required

F1, the applied force

Applying the formula

F1/A1= F2/A2

substute

F1/2=14700/0.2

2*14700= F1*0.2

29400= F1*0.2

F1= 29400/0.2

F1=147,000N

Hence, the applied force is 147,000N

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3 years ago