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3 years ago

6

Carla bought a shirt for $14 and a jacket for $69. She gave the cashier $100.

2 answers:

Inessa [10]3 years ago

6 0

Ur answer is 17 dollars cause u add 14 to 69 and u get 83 then you subtract 83 from 100 which equals 17

Jlenok [28]3 years ago

3 0

You add $14.00 + $69.00 = $83.00

Then you minus 83 from 100 and you get $17.00 Dollars to be exact.

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2 years ago

Read 2 more answers

Gregory knows that Triangle A B C is reflected onto Triangle A prime B prime C prime. Which statement about the figures is true?

ziro4ka [17]

Answer: if Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.

Explanation:

Given that a triangle ABC is reflected in triangle A'B'C'

Here reflection is done on a line

If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'

Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror

But note that corresponding images will only be perpendicular bisector to the line

So A and A' only will be corresponding so AA' will have mid point on line

Option 1 is right

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2 years ago

What is the first step in solving the following system of equations?

Gelneren [198K]

Answer:

B

Step-by-step explanation:

its b solve the first equation for y \

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2 years ago

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k0ka [10]

Answer:

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Step-by-step explanation:

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3 years ago

Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a

labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute $e^{0.4}$ by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

$e^{0.4}$ < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$ , where $M=|F^{N+1}(x)|$

$\leq \frac{3}{(3+1)!} |-0.4|^4$

$\leq \frac{3}{24} \times (0.4)^4$

$\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0

3 years ago