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LUCKY_DIMON [66]
3 years ago
10

Please answer this in two minutes

Mathematics
2 answers:
Sonja [21]3 years ago
5 0

Answer:

Not a triangle

Step-by-step explanation:

Side lengths do not adhere to the triangle inequality theorem. Which states that the sum of the side lengths of any 2 sides of a triangle must exceed the length of the third side.

Vladimir79 [104]3 years ago
3 0
Not a triangle because the two smaller numbers do not add up to a bigger number than 15
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Police Chase: A speeder traveling 40 miles per hour (in a 25 mph zone) passes a stopped police car which immediately takes off a
zubka84 [21]

Answer:

a. 18.34 s b. 327.92 m

Step-by-step explanation:

a. How long before the police car catches the speeder who continued traveling at 40 miles/hour

The acceleration of the car a in 10 s from 0 to 55 mi/h is a = (v - u)/t where u = initial velocity = 0 m/s, v = final velocity = 55 mi/h = 55 × 1609 m/3600 s = 24.58 m/s and t = time = 10 s.

So, a =  (v - u)/t =  (24.58 m/s - 0 m/s)/10 s = 24.58 m/s ÷ 10 s = 2.458 m/s².

The distance moved by the police car in 10 s is gotten from

s = ut + 1/2at² where u = initial velocity of police car = 0 m/s, a = acceleration = 2.458 m/s² and t = time = 10 s.

s = 0 m/s × 10 s + 1/2 × 2.458 m/s² (10)²

s = 0 m + 1/2 × 2.458 m/s² × 100 s²

s = 122.9 m

The distance moved when the police car is driving at 55 mi/h is s' = 24.58 t where t = driving time after attaining 55 mi/h

The total distance moved by the police car is thus S = s + s' = 122.9 + 24.58t

The total distance moved by the speeder is S' = 40t' mi = (40 × 1609 m/3600 s)t' =  17.88t' m where t' = time taken for police to catch up with speeder.

Since both distances are the same,

S' = S

17.88t' = 122.9 + 24.58t

Also, the time  taken for the police car to catch up with the speeder, t' = time taken for car to accelerate to 55 mi/h + rest of time taken for police car to catch up with speed, t

t' = 10 + t

So, substituting t' into the equation, we have

17.88t' = 122.9 + 24.58t

17.88(10 + t) = 122.9 + 24.58t

178.8 + 17.88t = 122.9 + 24.58t

17.88t - 24.58t = 122.9 - 178.8

-6.7t = -55.9

t = -55.9/-6.7

t = 8.34 s

So, t' = 10 + t

t' = 10 + 8.34

t' = 18.34 s

So, it will take 18.34 s before the police car catches the speeder who continued traveling at 40 miles/hour

b. how far before the police car catches the speeder who continued traveling at 40 miles/hour

Since the distance moved by the police car also equals the distance moved by the speeder, how far the police car will move before he catches the speeder is given by S' = 17.88t' = 17.88 × 18.34 s = 327.92 m

4 0
2 years ago
Find the surface area
xz_007 [3.2K]

Answer:

base -l*b - 13*6.5 - 84.5

6 0
3 years ago
Can anyone find the circumference in terms of pi?
qaws [65]

Answer:

20\pi

Step-by-step explanation:

The formula for circumference is 2\pir, where r stands for radius. Therefore, the circumference of this circle can be defined by:

2\pir

2\pi10

20\pi

Hope this helps :) Please contact me if you have any questions!

5 0
3 years ago
Read 2 more answers
Equation in slope y-intercept form and identify the slop and y-intercept of the line: 2x-5y=15
Dennis_Churaev [7]

Answer:

y=2/5x - 3

slope is 2/5

y intercept is -3

Step-by-step explanation:

6 0
3 years ago
An ice cream stand uses the expression 2 + 0.5x2+0.5x2, plus, 0, point, 5, x to determine the cost (in dollars) of an ice cream
Rashid [163]

Answer:

An ice cream cone with 5 scoops cost is, $4.5

Step-by-step explanation:

As per the statement:

An ice cream stand uses the expression 2+0.5x to determine the cost of an ice cream cone that has x scoops of ice cream.

⇒ Cost of an ice cream cone C(x) = 2+0.5x         .....[1]

Given: x = 5 scoops

We have to find the cost of an ice cream cone with 5 scoops cost.

Substitute the given value of x =5 in [1] we have;

C(5) = 2+0.5(5)

C(5) = 2+0.5 \times 5 = 2 + 2.5 = $4.5

Therefore, an ice cream cone with 5 scoops cost is, $4.5

3 0
3 years ago
Read 2 more answers
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