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insens350 [35]
3 years ago
14

1. How does inertia affect a person who is not wearing a seatbelt during a collision? 

Computers and Technology
2 answers:
Mice21 [21]3 years ago
8 0
He will get a violent shock nd might even fall forward 
Shtirlitz [24]3 years ago
4 0
Well the properties of inertia will keep the person in motion, even when the car has stopped. Therefore, the person will continue moving forward, as just as the car was moving.

:)

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write a C program the prints out the size of variables with the following C data types- int, long, unsigned, long long, double,
Anit [1.1K]

<u>C program for finding size of different data types</u>

#include <stdio.h>

//driver function

int main()

{

   int a;  //declaring a of type int

   float b; //declaring b of type float

   double c; //declaring c of type double

   char d; //declaring d of type char

   long e; //declaring e of type long

   long long f; //declaring f of type longlong

   unsigned g; //declaring g of type unsigned

   // Sizeof operator is used to evaluate the size of a variable

printf(" int data type contains: %lu bytes\n",sizeof(a));/*Finding size of int */

printf("float data type contains : %lu bytes\n",sizeof(b));/*Finding size of float */

printf("double data type contains: %lu bytes\n",sizeof(c));/*Finding size of double */

printf("char data type contains: %lu byte\n",sizeof(d));/*Finding size of char */

printf("long data type contains: %lu byte\n",sizeof(e));/*Finding size of long*/ printf("longlong data type contains: %lu byte\n",sizeof(f));/*Finding size of longlong */

printf("unsigned data type contains: %lu byte\n",sizeof(g)); /*Finding size of unsigned */

   return 0;

}

<u>Output</u>

int data type contains: 4 bytes

float data type contains : 4 bytes

double data type contains: 8 bytes

char data type contains: 1 byte

long data type contains: 8 byte

longlong data type contains: 8 byte

unsigned data type contains: 4 byte

4 0
3 years ago
Which of the following shows the assignment of a string to a variable? Select 3 options.
satela [25.4K]

Answer:

23, (23)

Explanation:

7 0
3 years ago
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Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

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DanielleElmas [232]
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