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Gnoma [55]
3 years ago
11

2- There are many different design parameters that are important to a cache’s overall performance. Below are listed parameters f

or different direct-mapped cache designs. Cache Data Size: 32 KiB Cache Block Size: 2 words Cache Access Time: 1 cycle Calculate the total number of bits required for the cache listed above, assuming a 32-bit address. Given that total size, find the total size of the closest direct-mapped cache with 16-word blocks of equal size or greater. Explain why the second cache, despite its larger data size, might provide slower performance than the first cache. You must show your work
Computers and Technology
1 answer:
katen-ka-za [31]3 years ago
5 0

Answer:

1. 2588672 bits

2. 4308992 bits

3. The larger the data size of the cache, the larger the area of ​​memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.

Explanation:

1. Number of bits in the first cache

Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))

total bits = 2^15 (1+14+(32*2^1)) = 2588672 bits

2. Number of bits in the Cache with 16 word blocks

Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))

total bits = 2^13(1 +13+(32*2^4)) = 4308992 bits

3. Caches are used to help achieve good performance with slow main memories. However, due to architectural limitations of cache, larger data size of cache are not as effective than the smaller data size. A larger cache will have a lower miss rate and a higher delay. The larger the data size of the cache, the larger the area of ​​memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.

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Answer:

The program to this question can be given as:

Program:

class Horse   //define class Horse

{  

private String name;   //define variables.

private String color;  

private int birthYear;  

//define set method.

public void setName(String name)  

{  

this.name = name; //set value of name.

}

public void setColor(String color)  

{  

this.color = color; //set value of color.  

}  

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this.birthYear = birthYear;  //set value of birthYear

}  

//define get method.

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{  

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public String getColor()

{  

return color;  //return color.

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{  

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{

private String raceNum;            //define variable.

public void setRace(String raceNum)    //define set method.

{

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public String getRace()

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{

public static void main(String[] args) //define main method.

{

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       System.out.println("The name of the horse is " + ob.getName()+"." +"\n"+  

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}

}

Output:

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It was born in 2008.

XXX has taken part in Five hundred meter races.

Explanation:

In the above program firstly we declare the class that is Horse in this class we define a variable that name is already given in the question which are name, color, and birthYear. In these variables are name and color datatype is string and the birthYear datatype is an integer because it stores the number. Then we use the get and set function in the get function we return all variable value. and in the set function, we set the values of the variable by this keyword. Then we declare another class that is RaceHorse this class inherit Horse class. In the RaceHorse class, we define a variable that is raceNum that's data type is a string in this class we also used the get and set function. Then we declare the main class in the main class we define the main method in the main method we create the above class object and call the set and get function and print the values of the function.

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