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Sveta_85 [38]
3 years ago
5

The shorter tree is 10.5 ft. tall, and casts a shadow that is 11.25 feet long.if the taller tree casts a 17.5 ft. shadow,how tal

l is the tree?
Mathematics
1 answer:
NARA [144]3 years ago
6 0
The tree is about 15.9 feet tall.
You might be interested in
Please help me with this thankyou​
DerKrebs [107]
The answer would be 60

The first think you would need to do would simply 144. Which would be 12.

Then you are going to want to multiply-5 by 12.
Which would be 60.
With 12 as a positive number, being greater or to than 60 then will become a positive.
7 0
2 years ago
PLease heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelp urgently
iren2701 [21]

Answer:

  1. 12n
  2. 4t
  3. 6 + n
  4. 6w
  5. d - 7
  6. 62 + h
  7. 20 - y
  8. 1/4z
  9. 20 - s
  10. 3/5c
  11. 4s
  12. u + v  

8 0
3 years ago
Read 2 more answers
A company is selling toothpicks. It costs $0.01 to produce each toothpick and a fixed cost of $60 a month for the company. If th
Lapatulllka [165]

Answer:

6,000 toothpicks

Step-by-step explanation:

In this question, we are trying to evaluate the number of toothpicks a company must sell to ensure that the money spent on production is exactly equal to revenue from sales.

What we do is this!

Let’s assign a variable to represent the number of tooth picks sold and produced by the company. Let us call this number x.

First, we evaluate the total amount spent on production of x toothpicks. From the question, we can see that the cost of producing a single toothpick is $0.01, hence, to produce x toothpicks, amount spent asides the fixed cost is $0.01 * x = $0.01x

Now, the total cost on production which includes the fixed cost of the company would be $(0.01x + 60). This is the total amount spent to produce the goods.

Now revenue from sales for x toothpicks at $0.02 each is $0.02x

Since we are looking to Breakeven, we equate the costs to the revenue.

0.01x + 60 = 0.02x

0.02x-0.01x = 60

0.01x = 60

x = 60/0.01 = 6,000 toothpicks

6 0
3 years ago
A store selling newspapers orders only n = 4 of a certain newspaper because the manager does not get many calls for that publica
umka2103 [35]

Answer:

a) The expected value is 2.680642

b) The minimun number of newspapers the manager should order is 6.

Step-by-step explanation:

a) Lets call X the demanded amount of newspapers demanded, and Y the amount of newspapers sold. Note that 4 newspapers are sold when at least four newspaper are demanded, but it can be <em>more</em> than that.

X is a random variable of Poisson distribution with mean \mu = 3 , and Y is a random variable with range {0, 1, 2, 3, 4}, with the following values

  • PY(k) = PX(k) = ε^(-3)*(3^k)/k! for k in {0,1,2,3}
  • PY(4) = 1 -PX(0) - PX(1) - PX(2) - PX (3)

we obtain:

PY(0) = ε^(-3) = 0.04978..

PY(1) = ε^(-3)*3^1/1! = 3*ε^(-3) = 0.14936

PY(2) = ε^(-3)*3^2/2! = 4.5*ε^(-3) = 0.22404

PY(3) = ε^(-3)*3^3/3! = 4.5*ε^(-3) = 0.22404

PY(4) = 1- (ε^(-3)*(1+3+4.5+4.5)) = 0.352768

E(Y) = 0*PY(0)+1*PY(1)+2*PY(2)+3*PY(3)+4*PY(4) =  0.14936 + 2*0.22404 + 3*0.22404+4*0.352768 = 2.680642

The store is <em>expected</em> to sell 2.680642 newspapers

b) The minimun number can be obtained by applying the cummulative distribution function of X until it reaches a value higher than 0.95. If we order that many newspapers, the probability to have a number of requests not higher than that value is more 0.95, therefore the probability to have more than that amount will be less than 0.05

we know that FX(3) = PX(0)+PX(1)+PX(2)+PX(3) = 0.04978+0.14936+0.22404+0.22404 = 0.647231

FX(4) = FX(3) + PX(4) = 0.647231+ε^(-3)*3^4/4! = 0.815262

FX(5) = 0.815262+ε^(-3)*3^5/5! = 0.91608

FX(6) = 0.91608+ε^(-3)*3^6/6! = 0.966489

So, if we ask for 6 newspapers, the probability of receiving at least 6 calls is 0.966489, and the probability to receive more calls than available newspapers will be less than 0.05.

I hope this helped you!

8 0
3 years ago
You can multiply -2.2 by 6.2 to find the total variation in water level. What decimal represents the total variation in water le
rewona [7]
Whatever she observed
4 0
3 years ago
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