Answer:
The probability is 3/95
Step-by-step explanation:
Okay this is a probability without replacement question.
Firstly we calculate the total number of coins = 7 + 9 + 4 = 20 coins
The probability that the first coin will be a dimes = number of dimes/total number of coins = 4/20 = 1/5
Now she removes a coin without replacement, if it was a dime, total number of coins becomes 19 and the total number of dimes becomes 3; Thus the probability of the second coins being a dimes = 3/19
Thus, the probability of both coins being dimes = probability of first coin being dimes * probability of second coins being dimes
= 1/5 * 3/19 = 3/95
First one is 6*5*4*3*2*4*3*2
second is 5*4*3*2*2
Answer:
well this "paul" could stand on his head or break a bone and his mother would HAVE to pay attention
Total tickets sold = 800
Total revenue = $3775
Ticket costs:
$3 per child,
$8 per adult,
$5 per senior citizen.
Of those who bought tickets, let
x = number of children
y = number of adults
z = senior citizens
Therefore
x + y + z = 800 (1)
3x + 8y + 5z = 3775 (2)
Twice as many children's tickets were sold as adults. Therefore
x = 2y (3)
Substitute (3) into (1) and (2).
2y + y + z = 800, or
3y + z = 800, or
z = 800 - 3y (4)
3(2y) + 8y + 5z = 3775, or
14y + 5z = 3775 (5)
Substtute (4) nto (5).
14y + 5(800 - 3y) = 3775
-y = -225
y = 225
From (4), obtain
z = 800 - 3y = 125
From (3), obtain
x = 2y = 450
Answer:
The number of tickets sold was:
450 children,
225 adults,
125 senior citizens.
