<span>If a transversal intersects two parallel lines, then <span>alternate interior angles are congruent
</span></span>If I managed to help you, please make sure to mark my answer as the "Brainliest" answer. Thanks! :)<span><span>
</span></span>
Answer:
x as a fraction: 11
Step-by-step explanation:
Variable x cannot be equal to −2 since division by zero is not defined. Multiply both sides of the equation by 9(x+2), the least common multiple of 9,x+2.
2 ( x+ 2) = 9 x 3
Use the distributive property to multiply 2 by x + 2.
2x + 4 = 9 x 3
Multiply 9 and 3 to get 27.
2x + 4 = 27
Subtract 4 from both sides.
2x = 27 - 4
Subtract 4 from 27 to get 23.
2x = 23
Divide both sides by 2.
x = 
Simplify
11
Hope it helps and have a great day! =D
~sunshine~
Answer:
Step-by-step explanation:
calculate the total
42+ 14 = 56
42/56 = x/100
4200 / 56x = 75
the answer is 75%
Answer:
2/5
Step-by-step explanation:
you want to start with the point on the left and then count 2 up to the line that the other point is on than you count over 5 to the point on the right
then you put rise over run which makes it 2/5
Answer:
1) w₁=4 - i w₂= -4 + i
2) w₁= 3 - i w₂= -3 + i
3) w₁= 1 + 2i w₂= - 1 - 2i
4) w₁= 2- 3i w₂= -2 + 3i
5) w₁= 5 - 2i w₂= -5 + 2i
6) w₁= 5 - 3i w₂= -5 + 3i
Step-by-step explanation:
The root of a complex number is given by:
![\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bz%7D%3D%5Csqrt%5Bn%5D%7Br%7D%28Cos%28%5Cfrac%7B%5Ctheta%2B2k%5Cpi%7D%7Bn%7D%29%20%2B%20i%20Sin%28%5Cfrac%7B%5Ctheta%2B2k%5Cpi%7D%7Bn%7D%29%29)
where:
r: is the module of the complex number
θ: is the angle of the complex number to the positive axis x
n: index of the root
1) z = 15 − 8i ⇒ r=17 θ= -0.4899 rad
w₁=
=4-i
w₂=
=-1+i
2) z = 8 − 6i ⇒ r=10 θ= -0.6435 rad
w₁=
= 3 - i
w₂=
= -3 + i
3) z = −3 + 4i ⇒ r=5 θ= -0.9316 rad
w₁=
= 1 + 2i
w₂=
= -1 - 2i
4) z = −5 − 12i ⇒ r=13 θ= 0.4426 rad
w₁=
= 2- 3i
w₂=
= -2 + 3i
5) z = 21 − 20i ⇒ r=29 θ= -0.8098 rad
w₁=
= 5 - 2i
w₂=
= -5 + 2i
6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad
w₁=
= 5 - 3i
w₂=
= -5 + 3i