Answer:
4 pairs of sock and a little bit of left over change.
Step-by-step explanation:
24.95 + 5.95x = 50
-24.95 -24.95
5.95x=25.05
/5.95 /5.95
x = 4.21
We drop the 0.21 because you cant have 0.21 pairs of socks and we get:
x=4
Answer:
-32r-12
Step-by-step explanation:
Solve by distributing the -4 (multiplying -4 by the numbers in parentheses)
Answer:
Option E is correct.
12 pairs of socks and 15 pairs of shorts did team buy each year.
Step-by-step explanation:
Let the number of pairs of socks be x and the number pairs of shorts be y.
As per the statement:
Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315.
⇒
.....[1]
It is also given that: This year they spent $342 to buy the same number of socks and shorts, because the socks now cost $6 a pair and the shorts cost $18.
⇒
.....[2]
Multiply equation [1] by 6 both sides we get;
.......[3]
Multiply equation [2] by 5 both sides we get;
.....[4]
Subtract equation [4] from [3] we get;
Divide both sides by 168 we get;
y = 15
Substitute the given values of y =15 in [1] we get;
5x+17(15) = 315
5x + 255 = 315
Subtract 255 from both sides we get;
5x = 60
Divide both sides by 5 we get;
x = 12
Therefore, 12 pairs of socks and 15 pairs of shorts did team buy each year.
Answer:
The optimal, vertex, value will be a minimum
Step-by-step explanation:
The given zeros of the quadratic relation are 3 and 3
The sign of the second differences of the quadratic relation = Positive
Whereby the two zeros are the same as x = 3, we have that the point 3 is the optimal value or vertex (the repeated point in the graph of the quadratic relation) of the quadratic relation
Whereby, the table of values for the quadratic relation from which the second difference is found starts from x = 3, we have;
To the right of the coordinate points of the zeros of the quadratic relation, the positive second difference in y-values gives as x increases, y increases which gives a positive slope
By the nature of the quadratic graph, the slope of the line to the left of the coordinate point of the zeros of the quadratic relation will be of opposite sign (or negative). The quadratic relation is cup shaped and the zeros, therefore, the optimal value will be a minimum of the quadratic relation
