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Gala2k [10]
3 years ago
14

If 1/x 1/x 1/x 1/x =24 what is x

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0
Would you please elaborate on what you would like to know?
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F(x) and g(x) are a differentiable function for all reals and h(x) = g[f(5x)]. The table below gives selected values for f(x), g
astraxan [27]
By the chain rule,

h(x)=g(f(5x))\implies h'(x)=5g'(f(5x))f'(5x)

so

h'(1)=5g'(f(5))f'(5)

It's kinda hard to tell which values are which in the table, but if I had to guess, you should get

h'(t)=5g'(f(5))f'(5)=5g'(2)(0)=0
5 0
3 years ago
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Find x? Nnnnnnnnnnnnnnnnnnnnnnn
coldgirl [10]
Cos(x) = 32/40 = 0.8   ⇒  x ≈ 37°
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4 years ago
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blondinia [14]
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3 years ago
A recent survey showed that in a sample of 100 elementary school teachers, 15 were single. In a sample of 180 high school teache
trapecia [35]

Answer:

By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single

Step-by-step explanation:

let p1  be the proportion of elementary teachers who were single

let p2 be the proportion of high school teachers who were single

Then, the null and alternative hypotheses are:

H_{0}: p2=p1

H_{a}: p2>p1

We need to calculate the test statistic of the sample proportion for elementary teachers who were single.

It can be calculated as follows:

\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of high school teachers who were single (\frac{36}{180} =0.2)
  • p is the proportion of elementary teachers who were single (\frac{15}{100} =0.15)
  • N is the sample size (180)

Using the numbers, we get

\frac{0.2-0.15}{\sqrt{\frac{0.15*0.85}{180} } } ≈ 1.88

Using z-table, corresponding  P-Value is ≈0.03

Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)

8 0
3 years ago
Consider the series 4+8+16+32+... <br> What is the common ratio?
Amiraneli [1.4K]
The common ratio is 24 x 2 = 88 x 2 = 1616 x 2 =32
Can I get Brainliest?
Thanks

7 0
3 years ago
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