Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
3 inches by 1 inches or 6 inches by 2 inches. Both answera are correct
Step-by-step explanation:
just an equivalent ratio
hope this helps can I get brainliest
Step-by-step explanation:
It's a question of trigonometry.
You need to remember that tangent (tan) stands for Perpendicular / Base.
So, tan P = QR / PR
By Pythagoras Theorem,
34² = 30² + x²
x² = 34² - 30²
x² = 1156 - 900
x² = 256
x = 16
Now, placing the values,
tan P = 30 / 16
tan P = 1.875
HOPE IT HELPS ^_^
When a function intersects with the x-axis, it's y value must be 0. That means when the straight line intersects with the axis, it's at the point (4k,0), so plugging those numbers into our original equation yields:
1: 1/2
2: about 1 1/2 hours
