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wlad13 [49]
3 years ago
8

Does anyone know any good Algebra 1 studying tips. Big tests coming up.

Mathematics
1 answer:
serious [3.7K]3 years ago
4 0

Answer:

Review your notes, make flashcards, go back to your textbook and solve problems you haven't solved. Just keep doing practice problems

You might be interested in
9× 3 1/2=<br> Which choice is the most reasonable answer?
icang [17]

Answer:

31.5 or 63/2

Step-by-step explanation:

to do this, first you need to transform the <u>mixed number</u> <em>(3 1/2)</em> into an <u>improper fraction</u>, to get 7/2.

then you just multiply 9 by 7/2

9/1 (7/2)

63/2 = 31.5

<em>both of the answers in bold are correct</em>

8 0
3 years ago
Can you help me with this please. Please show your work. Thx in advance
pentagon [3]
That is correct I think it is
4 0
3 years ago
Read 2 more answers
Please do my all question​
Kryger [21]

The factorization of the numbers is obtained as

(a) 36 = 2² x 3²,

(b) 60 = 2² x 3 x 5,

(c) 84 = 2² x 3 x 7,

(d) 99 = 3² x 11 and

(d) 180 = 2² x 3² x 5

<h3>Factor of the numbers</h3>

To factorize the numbers we use their factors as show below;

<h3>Factors of 36</h3>

36 = 2² x 3²

<h3>Factors of 60</h3>

60 = 2² x 3 x 5

<h3>Factors of 84</h3>

84 = 2² x 3 x 7

<h3>Factors of 99</h3>

99 = 3² x 11

<h3>Factors of 180</h3>

180 = 2² x 3² x 5

Thus, the factorization of the numbers is obtained as 36 = 2² x 3², 60 = 2² x 3 x 5, 84 = 2² x 3 x 7, 99 = 3² x 11 and 180 = 2² x 3² x 5.

Learn more about factorization here: brainly.com/question/25829061

#SPJ1

6 0
1 year ago
Given circle and circle with radii of 6cm and 4cm respectively.
noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

\angle EAF = \theta = 140^\circ

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

                                    = 14.653 cm

In circle C

\angle GCH = \theta = 140^\circ

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

                                    = 9.769 cm    

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is  1.5 times the length of GH

i.e.                   14.653  = 1.5 x 9.769

                       14.653 = 14.653

Hence proved.

                             

6 0
3 years ago
221 febrero 2021
DIA [1.3K]

Answer:

uhhh i would love to help but i cant speak that language

3 0
2 years ago
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