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3 years ago

The following data set is sorted in ascending order:

1 answer:

6 0

In statistics, the mean is the average of all data. You sum up all the data and divide to the number of data. Median, on the other hand, is just the middle term of the data when arranged from least to most.

So the measure that would change most is the mean. The new mean would be -5.82. While the new median would just move to the next data point which is 101.

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Find the perimeter (add all sides) of a square when side a= - 41x²

Dafna11 [192]

Answer:

-164x^2

Step-by-step explanation:

The Perimeter of a square is 4s where s is the length of 1 side.

So P=4(-41x^2) 41*4=164 ----> P=-164x^2

5 0

3 years ago

What is the MAXIMUM amount you should be spending on housing in a situation where your GROSS INCOME is $2000 per month? 1. For r

almond37 [142]

Answer:

the answer is a

Step-by-step explanation:

i took the test on gogo.net

5 0

3 years ago

For a test of upper h 0h0: pequals=0.50, the sample proportion is 0.470.47 based on a sample size of 100. use this information

otez555 [7]

The parts (a) to (c) can be completed using the equtaion y ⇔ Δ ∈ ∞, ㏒Δ ∀ x∈√a, a∈R.

8 0

3 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

case a) $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

case b) $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

case c) $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

case d) $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

the answer is

$x^{2}-2x-4=0$

5 0

3 years ago

Read 2 more answers

Please help me on this ! only the circled ones btw.

timurjin [86]

Knobibibuvuguguvuhhh

3 0

3 years ago