AREA OF A REGULAR OCTAGON FORMULA:
A = 2 (1 + √2) a²
A = 2 * (1 + √2) * 14²
A = 2 * (1 + 1.414) * 196
A = 2 * 2.414 * 196
A = 4.828 * 196
A = 946.288 cm²
Factor the following:
10 y^2 - 35 y + 30
Factor 5 out of 10 y^2 - 35 y + 30:
5 (2 y^2 - 7 y + 6)
Factor the quadratic 2 y^2 - 7 y + 6.
The coefficient of y^2 is 2 and the constant term is 6.
The product of 2 and 6 is 12.
The factors of 12 which sum to -7 are -3 and -4. So 2 y^2 - 7 y + 6 = 2 y^2 - 4 y - 3 y + 6 = y (2 y - 3) - 2 (2 y - 3):
5 y (2 y - 3) - 2 (2 y - 3)
Factor 2 y - 3 from y (2 y - 3) - 2 (2 y - 3):
Answer: 5 (2 y - 3) (y - 2)
Answer:
A
Step-by-step explanation:
hypotenuse is
a squared+ b squared= c squared
3 squared +2 squared=6 squared
so the actual answer is the square root of 6!
pls mark me as brainliest!!<3
Answer:
It is 1 4/7
Step-by-step explanation: