Probably 2520$ that will be how many she would hav
Answer:
a.) ![N(x) = N_{0} e^{bx}](https://tex.z-dn.net/?f=N%28x%29%20%3D%20%20N_%7B0%7D%20e%5E%7Bbx%7D)
b.) therefore b = ![\ln \frac{2142}{2100} = \ln (1.02) = 0.0198](https://tex.z-dn.net/?f=%5Cln%20%5Cfrac%7B2142%7D%7B2100%7D%20%20%3D%20%20%5Cln%20%281.02%29%20%3D%200.0198)
b is the rate of increase of number of members
c.) The club will not be able to get more than 5000 members during its first year.
Step-by-step explanation:
i) the club started with 2100 members.
so we can write
= 2100.
a.) so we can write the equation as an exponential function given by
where x is in months and b is a constant and N(x) is the number of members in the online music sharing club .
therefore 2142 = 2100
= 2100![e^{b}](https://tex.z-dn.net/?f=e%5E%7Bb%7D)
b.) therefore b = ![\ln \frac{2142}{2100} = \ln (1.02) = 0.0198](https://tex.z-dn.net/?f=%5Cln%20%5Cfrac%7B2142%7D%7B2100%7D%20%20%3D%20%20%5Cln%20%281.02%29%20%3D%200.0198)
b is the rate of increase of number of members
c.) Will the club have more than 5000 members during its first year? Justify your reasoning.
5000 = 2100![e^{0.0198x}](https://tex.z-dn.net/?f=e%5E%7B0.0198x%7D)
therefore x = ![\frac{1}{0.0198} \ln{(\frac{5000}{2100} )} = 43.81 \hspace{0.1cm}months](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B0.0198%7D%20%5Cln%7B%28%5Cfrac%7B5000%7D%7B2100%7D%20%29%7D%20%20%3D%20%2043.81%20%5Chspace%7B0.1cm%7Dmonths)
The club will not be able to get more than 5000 members during its first year.
X equals 4 because 2 times 2 equals 4 and then 4 times 4 =16
Well I am going to guess and i don't know if it right but 156.25ml
Answer:
idk refrace your question
Step-by-step explanation: