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3 years ago

PLEASE HELP WILL MARK FIRST RIGHT ANSWER AS BRAINIEST!!!!

Mathematics

1 answer:

zavuch27 [327]3 years ago

8 0

Answer:

110 degrees is the largest angle

Step-by-step explanation:

The angles in a pentagon add up to 540 degrees. In general, an n-sided polygon has angles that add up to 180*(n-2) where n is the number of sides. So, we're looking for 5 consecutive numbers that add up to 540. So, the five angles are 106, 107, 108, 109, and 110.

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Can someone help? 25 points

zavuch27 [327]

Answer:

x= 156

Step-by-step explanation:

i had a test with the same question, i promise its right :)

6 0

3 years ago

Read 2 more answers

Write (-5+8i)+(-5-8i) as a complex number in standard form

gizmo_the_mogwai [7]

$(-5+8i)+(-5-8i) =
-5+8i-5-8i=-10$

5 0

3 years ago

What is the remainder of (4x2 + 7x-1)= (4 + x)?<br>A. -9x – 1<br>B.23x – 1<br>C.35<br>D.-37

bearhunter [10]

Answer: I don't know what you meant by remainder but i hope this helps :)

$x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\$

Step-by-step explanation:

$\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}$

$\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\$

$\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}$

6 0

2 years ago

Read 2 more answers

An isosceles triangle has a perimeter of 18 cm. Find a function that models its area A in terms of the length of its base b.

IgorLugansk [536]

So.... notice the picture below

now, we know what the "height" or "altitude" is
now, we also know the perimeter is 18cm

so, k + k + b = 18
or 2k + b = 18
thus $\bf k=\cfrac{18-b}{2}$

so... one can say that $\bf \textit{area of a triangle}=A=\cfrac{1}{2}bh\qquad 
\begin{cases}
b=b
\\\\
h=\sqrt{k^2-\left( \frac{b}{2} \right)^2}
\\\\
h=\sqrt{k^2-\frac{b^2}{4}}\\
--------------\\
k=\frac{18-b}{2}\qquad thus\\
--------------\\
h=\sqrt{\left( \frac{18-b}{2} \right)^2-\frac{b^2}{4}}
\end{cases}\\\\
-----------------------------\\\\
A=\cfrac{1}{2}\cdot b\cdot \sqrt{\left( \frac{18-b}{2} \right)^2-\frac{b^2}{4}}$

and you can simplify it if you wish.. not sure you have to

7 0

2 years ago

98 points possible

Pavel [41]

Answer:

Step-by-step explanation:

symmetry with respect to y-axis for y=f(x) means f(-x)=f(x)

in this case, y = f(x) = x / (x^2+4)

f(-x) = -x / ((-x)^2+4) = -x / (x^2+4) = -f(x)

so it is not symmetric to y-axis

symmetry with respect to x-axis for x=g(y) means g(-y)=g(y)

in this case, y = x / (x^2+4)

y*(x^2+4) = x

y*x^2 + 4y - x = 0

substitute -y into g(y)

(-y)*x^2 +4(-y) - x = 0

-y*x^2 - 4y - x = 0

y*x^2 + 4y + x = 0

so g(-y) is not equal to g(y)

so it is not symmetric to x-axis

8 0

3 years ago

Read 2 more answers