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3 years ago

Y=(2x-3)^5(2-x^4)^3 differentiate the function please

1 answer:

5 0

$\bf y=(2x-3)^5(2-x^4)^3\\\\
-------------------------------\\\\
\cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]}
\\\\\\
\cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2
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\cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)]
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\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3]
\\\\\\
\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)$

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PLZ HELP i need the answer now

VARVARA [1.3K]

Answer:

1/5^9

Step-by-step explanation:

You keep the 5 the same

Then you subtract the exponents...

-6 - 3 = -9

Since it’s negative and you can’t have a negative exponent you have to put a 1 as the numerator. So...

1/5^9

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3 years ago

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Answer:

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3 years ago

The sum of liz's and melinda's ages is 28. if liz was 1/3 melinda's age 6 years ago, how old will liz be next year?

Mrrafil [7]

The first thing we must do for this case is to define variables:
We have then:
x: liz's age
y: melinda's age
We now write the system of equations:
$x + y = 28

x-6 = (1/3) (y-6)$
By solving the system graphically we have that the age of each one is currently:
$x = 10

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$x + 1 = 10 + 1 = 11
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Note: see attached image for the graphic solution.

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3 years ago

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lisabon 2012 [21]

<h3>Answer: Choice B</h3>

==========================================

Explanation:

Here's a slightly more detailed breakdown of what's going on

3x + 2y = 15 ... start with the first equation

3x + 2( y ) = 15 .... the parenthesis don't change the expression

3x + 2( 3x+5) = 15 ... replace y with 3x+5; since y = 3x+5

From here, you solve for x like you would any other single variable equation. Once you know x, you can determine y through y = 3x+5.

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2 years ago

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shtirl [24]

Answer:

Step-by-step explanation:

log_3 (81)

set equal to x

log_3 (81) = x

saying this out loud is "x equals 3 raised to what power is 81"

notice that it is the same as

3^x = 81

so x equals 4

7 0

3 years ago