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Ronch [10]
3 years ago
10

When solved for x, which inequality represents the number line?

Mathematics
2 answers:
romanna [79]3 years ago
6 0
I think it is answer is b
ser-zykov [4K]3 years ago
4 0
The answer might be B
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Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 6.2 parts
vovikov84 [41]

Answer:

H0 : μ = 6.2

H1 : μ ≠ 6.2

Step-by-step explanation:

Population mean, μ = 6.2 ppm

The hypothesis :

Null, H0 : = The mean level of Ozone is normally 6.2 ppm ;

The alternative hypothesis is the researcher's claim that the current ozone level is not normal, that is it may be higher or lower than the normal value in ppm

Hence, the hypothesis could be written as :

H0 : μ = 6.2

H1 : μ ≠ 6.2

5 0
3 years ago
Find the ratio of x to y is 5y=3x
Colt1911 [192]

Answer:

\frac{x}{y} = \frac{5}{3}

Step-by-step explanation:

given 5y = 3x ( divide both sides by 3 )

\frac{5}{3} y = x ( divide both sides by y )

\frac{5}{3} = \frac{x}{y}




5 0
3 years ago
Read 2 more answers
The length of a side of the base of a square pyramid is 10 inches. The height of each triangular face is 12 inches. What is the
galben [10]

Answer:

it's D

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
PLEASE HELP Meeeeeeeeeeeeeeeeee
klemol [59]
The answer is A.Use a compound interest calculator. Multiple sites to use. For me, I had to use my head for a while
3 0
3 years ago
A study was done to determine the average number of homes that a homeowner owns in his or her lifetime. For the 60 homeowners su
const2013 [10]

Answer:

D) (3.67, 4.73)

Step-by-step explanation:

Confidence Interval for the true average number of homes that a person owns in his or her lifetimecan be calculated using M±ME where

  • M is the average number of home owned (4.2)
  • ME is the margin of error from the mean

And margin of error (ME) can be calculated as

ME=\frac{z*s}{\sqrt{N} } where

  • z is the corresponding statistic in the given confidence level(1.96)
  • s is the standard deviation of the sample(2.1)
  • N is the sample size (60)

Putting the numbers we get ME=\frac{1.96*2.1}{\sqrt{60} }≈0.53

Then the 95% confidence interval is 4.2±0.53 or (3.67, 4.73)

6 0
2 years ago
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