The solution to the problem is as follows:
let
R = $619.15 periodic payment
i = 0.0676/12 the rate per month
n = 48 periods
S = the future value of an ordinary annuity
S = R[((1 + i)^n - 1)/i]
S = 619.15*[(1 + 0.0676/12)^48 - 1)/(0.0676/12)]
S = $34,015.99
I hope my answer has come to your help. God bless and have a nice day ahead!
So, givens: total lesson cost of $260, total lessons taken are 6, and the first lesson costs 1.5 (or 3/2) as much as the additional lessons.
First thing to do is to figure out how many additional lessons are in that, which are 5.
Then you can make a 1 variable equation with the information you have. I’m using x as my variable.
260= 3/2x + 5x
Combine like terms.
260 = 13/2x
Divide both sides by 13/2 (treat it as a fraction, and if your calculator cannot make fractions, then decimal might help for this. 13/2=6.5)
X=40
Answer:
Area = 20 ft²
Step-by-step explanation:
Area of a thrombus
½ × d1 × d2
½ × 5 × 8
20
Answer:
The answer is A) y+4 =3(x+3)
Step-by-step explanation:
The slope is the rate of change, which you can see from the graph is m = 3/1 = 3.
Your options are given in point-slope form:
y-y1=m(x-x1)
Pick a point from the graph. I used;
(-3, -4). Now plug this into your point slope form equation.
y-(-4) = 3(x-(-3))
y+4=3(x+3)
6= 4(z+9)/y+2
6y +12 =4(z+9)
6y=4(z+9) -12
y=(4(z+9)-12)/6
y=2z+18-6/3
y=2z+12 /3
