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Dominik [7]
3 years ago
12

The length of the hypotenuse of a right triangle is 24. If the length of one leg is 8, what is approximate length of the other l

eg.
Mathematics
1 answer:
Verdich [7]3 years ago
4 0

Something that a right triangle is characterised by is the fact that we may use Pythagoras' theorem to find the length of any one of its sides, given that we know the length of the other two sides. Here, we know the length of the hypotenuse and one other side, therefor we can easily use the theorem to solve for the remaining side.

Now, Pythagoras' Theorem is defined as follows:

c^2 = a^2 + b^2, where c is the length of the hypotenuse and a and b are the lengths of the other two sides.

Given that we know that c = 24 and a = 8, we can find b by substituting c and a into the formula we defined above:

c^2 = a^2 + b^2

24^2 = 8^2 + b^2 (Substitute c = 24 and a = 8)

b^2 = 24^2 - 8^2 (Subtract 8^2 from both sides)

b = √(24^2 - 8^2) (Take the square root of both sides)

b = √512 (Evaluate 24^2 - 8^2)

b = 16√2 (Simplify √512)

= 22.627 (to three decimal places)

I wasn't sure about whether by 'approximate length' you meant for the length to be rounded to a certain number of decimal places or whether you were meant to do more of an estimate based on your knowledge of surds and powers. If you need any more clarification however don't hesitate to comment below.

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Answer:

cos 2Ф = - 161/289 , tan 2Ф = - 240/161

Step-by-step explanation:

* Lets explain how to solve the problem

∵ cos Ф = - 8/17

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∵ sin²Ф + cos²Ф = 1

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∴ sin²Ф + 64/289 = 1

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∴ sin²Ф = 225/289 ⇒ take √ for both sides

∴ sin Ф = ± 15/17

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∵ cos 2Ф = 2cos²Ф - 1 ⇒ the rule of the double angle

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∴ sin 2Ф = 2 × (-15/17) × (-8/17) = 240/289

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The square root of 1296 is 6.


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Triangle V U W is shown. The length of side W V is 6 centimeters, the length of side W U is 3 StartRoot 3 EndRoot centimeters, a
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Answer:

The angle measures of Δ VUW are m∠V = 60°, m∠U = 90°, m∠W = 30° ⇒ last answer

Step-by-step explanation:

In any triangle if the sum of the squares of the shortest two sides is equal to the square of the longest side, then the triangle is a right triangle and the angle opposite to the longest side is the right angle

In Δ VUW

∵ WV = 6 cm

∵ WU = 3\sqrt{3} cm

∵ UV = 3 cm

- Use the rule above tho check if it is a right Δ or not

∴ The longest side is WV

∴ The shortest two sides are WU and UV

∵ (WV)² = (6)² = 36

∵ (WU)² + (UV)² = (3\sqrt{3} )² + (3)² = 27 + 9 = 36

∴ (WV)² =  (WU)² + (UV)²

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Let us use the trigonometry ratios to find m∠W and m∠V

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∵ sin(∠W) = \frac{UV}{WV}

∵ sin(∠W) = \frac{3}{6}=\frac{1}{2}

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∴ ∠W = sin^{-1}(\frac{1}{2})

∴ m∠W = 30°

∵ WU is the opposite side of ∠V

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∵ sin(∠V) = \frac{WU}{WV}

∵ sin(∠V) = \frac{3\sqrt{3}}{6}=\frac{\sqrt{3}}{2}

- Use sin^{-1} to find ∠V

∴ ∠V = sin^{-1}(\frac{\sqrt{3}}{2})

∴ m∠V = 60°

The angle measures of Δ VUW are m∠V = 60°, m∠U = 90°, m∠W = 30°

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