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Korvikt [17]
3 years ago
8

How much does the 2020 honda civic si 4 door sedan summer w summer tires depreciate in total over 5 years ?

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

10,000-15,000

Step-by-step explanation:

You might be interested in
LOOK AT PICTURE look at picture
MAVERICK [17]

Answer:

-25.776

Step-by-step explanation:

-7.2

x 3.58

Multiply to get the sums and add them together to get your answer.

4 0
3 years ago
How do you solve this? Thank you
V125BC [204]
2)

a)

\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
(4x^5\cdot x^{\frac{1}{3}})+(2x^4\cdot x^{\frac{1}{3}})-(7x^3\cdot x^{\frac{1}{3}})+(3x^2\cdot x^{\frac{1}{3}})\\\\+(9x^1\cdot x^{\frac{1}{3}})-(1\cdot x^{\frac{1}{3}})
\\\\\\
4x^{5+\frac{1}{3}}+2x^{4+\frac{1}{3}}-7x^{3+\frac{1}{3}}+9x^{1+\frac{1}{3}}-x^{\frac{1}{3}}

\bf 4x^{\frac{16}{3}}+2x^{\frac{13}{3}}-7x^{\frac{10}{3}}+9x^{\frac{4}{3}}-x^{\frac{1}{3}}
\\\\\\
4\sqrt[3]{x^{16}}+2\sqrt[3]{x^{13}}-7\sqrt[3]{x^{10}}+9\sqrt[3]{x^4}-\sqrt[3]{x}

b)

\bf \cfrac{4x^5+2x^4-7x^3+3x^2+9x-1}{x^{\frac{1}{3}}}\impliedby \textit{distributing the denominator}
\\\\\\
\cfrac{4x^5}{x^{\frac{1}{3}}}+\cfrac{2x^4}{x^{\frac{1}{3}}}-\cfrac{7x^3}{x^{\frac{1}{3}}}+\cfrac{3x^2}{x^{\frac{1}{3}}}+\cfrac{9x}{x^{\frac{1}{3}}}-\cfrac{1}{x^{\frac{1}{3}}}
\\\\\\
(4x^5\cdot x^{-\frac{1}{3}})+(2x^4\cdot x^{-\frac{1}{3}})-(7x^3\cdot x^{-\frac{1}{3}})+(3x^2\cdot x^{-\frac{1}{3}})\\\\+(9x^1\cdot x^{-\frac{1}{3}})-(1\cdot x^{-\frac{1}{3}})

\bf 4x^{5-\frac{1}{3}}+2x^{4-\frac{1}{3}}-7x^{3-\frac{1}{3}}+9x^{1-\frac{1}{3}}-x^{-\frac{1}{3}}
\\\\\\
4x^{\frac{14}{3}}+2x^{\frac{11}{3}}-7x^{\frac{8}{3}}+9x^{\frac{2}{3}}-x^{-\frac{1}{3}}
\\\\\\
4\sqrt[3]{x^{14}}+2\sqrt[3]{x^{11}}-7\sqrt[3]{x^{8}}+9\sqrt[3]{x^{2}}-\frac{1}{\sqrt[3]{x}}



3)

\bf \begin{cases}
f(x)=\sqrt{x}-5x\implies &f(x)x^{\frac{1}{2}}-5x\\\\
g(x)=5x^2-2x+\sqrt[5]{x}\implies &g(x)=5x^2-2x+x^{\frac{1}{5}}
\end{cases}
\\\\\\
\textit{let's multiply the terms from f(x) by each term in g(x)}
\\\\\\
x^{\frac{1}{2}}(5x^2-2x+x^{\frac{1}{5}})\implies x^{\frac{1}{2}}5x^2-x^{\frac{1}{2}}2x+x^{\frac{1}{2}}x^{\frac{1}{5}}

\bf 5x^{\frac{1}{2}+2}-2x^{\frac{1}{2}+1}+x^{\frac{1}{2}+\frac{1}{5}}\implies \boxed{5x^{\frac{5}{2}}-2x^{\frac{3}{2}}+x^{\frac{7}{10}}}
\\\\\\
-5x(5x^2-2x+x^{\frac{1}{5}})\implies -5x5x^2-5x2x+5xx^{\frac{1}{5}}
\\\\\\
-25x^3+10x^2-5x^{1+\frac{1}{5}}\implies \boxed{-25x^3+10x^2-5x^{\frac{6}{5}}}

\bf 5\sqrt{x^5}-2\sqrt{x^3}+\sqrt[10]{x^7}-25x^3+10x^2-5\sqrt[5]{x^6}
6 0
3 years ago
What is the volume of the sphere?
Ilia_Sergeevich [38]

Answer:

V = 4/3 pi or approximately 4.187 ft^3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

The radius is 1 ft

V = 4/3 pi (1)^3

V = 4/3 pi

We can approximate pi by 3.14

V = 4/3 (3.14)

V = 4.186666666 ft^3

7 0
3 years ago
Read 2 more answers
Can someone help me with these 4 questions please :) .
butalik [34]

1.

60² + 30² = 4500²

Opposite corner = 67.08 ft.

//

2.

6² + 8² = 100²

The wire must be 10 ft.

//

3.

7² + 14² = 245²

The rope is 15.65 ft.

//

4.

180² + 300² = 122400²

He ran 349.85 ft.

//

I'm not too sure about question 3.

8 0
3 years ago
Help me In sick and don’t feel like doing their rn tbh
castortr0y [4]

Answer:

1.. \:  \: 64 - 40 = 24 \\ so.\% \:  \\  \frac{24}{40}  \times 100 = 60\% \\

............................

1-e

2-h

3-f

4- c

5-d

6-i

7-b

8-a

9-l

10-k

11-j

12-g

5 0
3 years ago
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