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Citrus2011 [14]
3 years ago
7

Which of the following is equivalent to 7-2(x+2) < 4-3(1 - x)?

Mathematics
1 answer:
iren [92.7K]3 years ago
5 0

Answer:

-x<-16

Step-by-step explanation:

4-3(1-x)

x=-1

7-2(x+2)

x=2

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What is 1/x^2 in the power of x
Serhud [2]

we have given that \frac{1}{x^2}.

we need to express this interms of power of x .

we know that \frac{1}{x^n} =x^-n.

in place of n we have 2 .so \frac{1}{x^2} =x^-2.

so this will be the expression interms of power of x .

6 0
3 years ago
Why will the value of y for the function y equals 5x + 1 always be greater than that of y equals 4x + 1 with X greater than 1?
klemol [59]
You mean
the linear equations, 5x-y+1=0,4x-y+1=0
the slopes are 5 and 4 respectively.
it is clear that slope of first equation is greater that is it has a steeper graph therefore it Will always be greater than the other for x > 1
the same can be done by calculus; differentiation.

note y=5x+1 is always greater than y=4x+1 for all x>1
4 0
3 years ago
Read 2 more answers
Please help me with this question! i will give brainiest if correct! (if you show me how to lol i have no idea how)
Nitella [24]

Answer:

  • y(2x² + y) / x(5y² - 6x)

Step-by-step explanation:

<u>Simplify the numerator:</u>

  • 1/x² + 2/y =
  • y/(x²y) + 2x²/(x²y) =
  • (2x² + y)/(x²y)

<u>Simplify the denominator:</u>

  • 5/x - 6/y² =
  • 5y²/(xy²) - 6x/(xy²) =
  • (5y² - 6x) / (xy²)

<u>Simplify the fraction:</u>

  • (2x² + y)/(x²y) ÷ (5y² - 6x) / (xy²) =
  • (2x² + y)/(x²y) × xy² / (5y² - 6x) =
  • y(2x² + y) / x(5y² - 6x)
7 0
3 years ago
Given the perimeter of a square find the length of one side using the appropriate formula
Lady bird [3.3K]
With a square, all you need to do to find the length of one side is to divide the perimeter by 4. If it is the area you are calculating, then you need to find the square root. For that equation the answer is 24.
8 0
3 years ago
H(y)=-3y^2+5<br> p(y)=y^3-7y<br> Find (h-p)(y)
gladu [14]

(h-p))(y) = -y^3-3y^2+7y+5

Step-by-step explanation:

Given

h(y) = -3y^2+5\\p(y) = y^3-7y

We have to find the difference of two functions given

So,

(h-p)(y) = h(y) - p(y)\\= (-3y^2+5)-(y^3-7y)\\=-3y^2+5-y^3+7y\\=-y^3-3y^2+7y+5

Hence,

(h-p))(y) = -y^3-3y^2+7y+5

Keywords: Functions, variables

Learn more about functions at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

5 0
3 years ago
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