A - 1.2b = - 3 ⇒ eq. 1
0.2b + 0.6a = 12 ⇒ eq. 2
a - 1.2b = - 3
a = 1.2b - 3 ⇒ eq. 3
Substitute eq. 3 to eq. 2
0.2b + 0.6(1.2b - 3) = 12
0.2b + .72b - 1.8 = 12
Combine like terms
0.92b = 12 + 1.8
0.92b = 13.8 ⇒ divide both sides by 0.92 to get the value of b
<span>b = 15
</span>Substitute the value of b to eq. 3
a = 1.2b - 3
a = 1.2(15) - 3
<span>a = 15
</span>to check: substitute the values of a and b to:
eq. 1
a - 1.2b = - 3
15 - (1.2)(15) = -3
15 - 18 = - 3
- 3 = -3 ⇒ correct!
eq. 2
0.2b + 0.6a = 12
(0.2)(15) + (0.6)(15) = 12
3 + 9 = 12
12 = 12 ⇒ correct!
Well, we know the slope is 3/2, what's the midpoint of those anyway?
so, what's the equation of a line whose slope is 3/2 and runs through 2,7?
Answer:
3,234 a 3b 3
Step-by-step explanation:
Answer:
6a + 24
Step-by-step explanation:
-12a + 24 + 18a = 6a + 24
Hi, thank you for posting your question.
This problem can be solved through ratio and proportion which can be applied to similar triangles like that shown in the figure. By ratio and proprotion,
AQ/AC = AP/AB
x/(40+x) = 7/(35+7)
Thus, x = 8
