Answer:
6.58 I could be wrong but that's pretty much it is it all students together in total?
Step-by-step explanation:
just add 1.94+0.97+1.8+1.87=6.58
You should get it now from my previous answer.
But to apply it.
9 - 8b + 6b
9 + (-8b + 6b) <- Collect like bases (b)
9 + (-2b)
9 - 2b
Therefore it simplified is 9 - 2b
Answer:
Step-by-step explanation:
Given that
Sample size = n = 8: sample mean = 36.5 and s = sample std dev = 7.4 minutes
98% CI using t = (28.7, 44.3) with margin of error as 7.8
Now if sigma = population std dev is known we use Z critical value
Margin of error = 2.33*8.7/\sqrt 8 = 7.167
CI = (36.5 ±7.167)
This is not wider than that used using t distribution
The margin of error of u is ___7.167
98% confidence interval using the standard normal distribution is (29.333__,43.667__)
d)the confidence interval found using the standard normal distrubution is narrower than the confidence interval found using the students t-distribution
First draw a line on the smallest number, and one on the largest. then calculate the midpoint (n+1)/2 the value, and draw that line in the middle. calculate upper quartile and lower quartile and draw lines on them. draw a line between the tops of the quartiles and one between the bottom, and from the middle of the lines to the minimum and maximum. sorry if not explained well
It is a positive line with a slope of 2/3 and a y-intercept of -5.