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Lapatulllka [165]
3 years ago
8

the area of a rectangular pyramid is 65yd^2. the length of the playground is 3 yards longer than twice it's width. find the leng

th and the width of the playground.
Mathematics
1 answer:
schepotkina [342]3 years ago
4 0
The area formula for a rectangle = Length x Width
Let length = L and width = W.
We also know that the length is 3 yards longer than twice it's width.
SO this means L = 3 PLUS 2 times W
L = 3 + 2W
Now plug that into the area formula and we get:
Area = (3 + 2W) x W
You'll need to multiply everything in the brackets by W.
So what would (3 + 2W)x W = ?
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Step-by-step explanation:

 Given the equation:

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\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}

- Multiply both sides of the equation by (m+3)(3-m) and simplify:

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- Multiply both sides by m-3:

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- Apply Distributive property and simplify:

(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0

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(m-3)^2=0\\\\m=3

In order to verify it, you must substitute m=3 into the equation and solve it:

\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}

<em>NO SOLUTION</em>

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