Area of the rectangle is given as = 16 square inches
We know
Length * width = Area
Then
Width = Area/Length
Now
Perimeter = 2 (Length + Width)
Perimeter = 2[ {Length + (Area/Length)}]
Perimeter = 2[Length + (16/Length)]
When d(Perimeter)/d(length) = 0,
Then
2[Length + (16/Length)] = 0
Length + (16/Length) = 0
Length^2 + 16 = 0
(Length)^2 = -(4)^2
Then
Length = 4 inches
Now
Width = Area/Length
= 16/4
= 4 inches.
Answer:
B
Step-by-step explanation:
It is transitive property of equality
and it states that if we consider a b and c
anf if a=b and b=c
then a=c
Draw a right triangle ABC with, the point where the top touches the ground and one leg, BC, the stump, measuring 14 ft.
The height of the tree = hypotenuse + stump BC (14 ft)
If the ∠ of inclination = 43°, then ∠ CAB = 37°
Now let's apply the law of sine:
sin 37°/14 = sin 43°/AB →and AB = 14.sin 43°/sin 37° = 15.86
Hypotenise² = AB² + CB²
Hypotenuse² = 15.85² + 14² = 447.22 → and Hypotenuse = 21.14 ft
Tree Height = hypotenuse + stump = 21.14 + 14 ≈ 35 ft
Answer:
hypotenuse
Step-by-step explanation:
15^2 + 11^2=c^2
18. 6 in or 19 in
