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kolezko [41]
4 years ago
6

Solve the following system of equations by substitution and select the correct answer below:

Mathematics
2 answers:
Bingel [31]4 years ago
6 0

Answer:


Step-by-step explanation:

2x-8y=32

Alexxx [7]4 years ago
5 0
Okay so for substitution, chose one of  of the equations to solve for x. Let's solve for the second one. So you have 2x-8y=32.
Start by adding 8y to both sides:
 2x=8y+32.
Then you have to get x by itself so you divide both sides by 2 which will give you:
 x=4y+16.

Now you have:
6x-4y=36
x=4y+16 (this was 2x-8y=32)

Now, plug in the second equation to the first one. You would do so by plugging in the second equation to where you see x. You would have:
6(4y+16)-4y=36

Now, multiply the 6 with the 4y and 16. you would then have:
24y+96-4y=36.

Now, combine your like terms to get:
20y+96=36
Then subtract 96 to both sides:
20y=-60
Then divide both sides so that you have y all by itself:
y=-30!

You now have the answer for y, so now plug what you got for y into the other equation: x+4y=16: 
x+4(-30)=60
Solve for x:
x-120=60 
add 120 to both sides:
x=180!
so Your answer is Y=-30 and X=180

I hope this helped:)


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Step-by-step explanation:

The given system of equations is.......

-x-3y=-17\\ \\ 2x-6y=-26

So, the augmented matrix will be:   \left[\begin{array}{cccc}-1&-3&|&-17\\2&-6&|&-26\\\end{array}\right]

Now, we will transform the augmented matrix to the reduced row echelon form using row operations.

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\left[\begin{array}{cccc}1&3&|&17\\2&-6&|&-26\\\end{array}\right]

<u>Row operation 2:</u>  Add -2 times the 1st row to the 2nd row. So.......

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<u>Row operation 3:</u>  Multiply the 2nd row by -\frac{1}{12}. So.......

\left[\begin{array}{cccc}1&3&|&17\\0&1&|&5\\\end{array}\right]

<u>Row operation 4:</u>  Add -3 times the 2nd row to the 1st row. So........

\left[\begin{array}{cccc}1&0&|&2\\0&1&|&5\\\end{array}\right]

Now, from this reduced row echelon form of the augmented matrix, we can get that x=2 and y=5

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