The first number after that matching the criteria is 106644, as 33 is below so the closest one has to be at 44.
Find the powers 
$a^{2}=5+2 \sqrt{6}$
$a^{3}=11 \sqrt{2}+9 \sqrt{3}$
The cubic term gives us a clue, we can use a linear combination to eliminate the root 3 term $a^{3}-9 a=2 \sqrt{2}$ Square $\left(a^{3}-9 a\right)^{2}=8$ which gives one solution. Expand we have $a^{6}-18 a^{4}-81 a^{2}=8$ Hence the polynomial $x^{6}-18 x^{4}-81 x^{2}-8$ will have a as a solution.
Note this is not the simplest solution as $x^{6}-18 x^{4}-81 x^{2}-8=\left(x^{2}-8\right)\left(x^{4}-10 x^{2}+1\right)$
so fits with the other answers.
27 pots..... I think. You have to divide the 81 in 81/4 by 3.
<span> The answer will be 2 There is only one distinct triangle possible, with m∠N ≈ 33°.</span>
Answer:
you forgot to attach it lol
Step-by-step explanation: