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Ksju [112]
3 years ago
7

Adding/subtracting mixed fractions

Mathematics
2 answers:
pav-90 [236]3 years ago
7 0
Hey there Kim!

Question #1

    \left[\begin{array}{ccc}  \left[\begin{array}{ccc}\boxed{\boxed{ 1\frac{1}{5} + 3\frac{2}{5}}} \end{array}\right] \end{array}\right] = \boxed{ \frac{23}{5}} \  
 \\ \\ \\  \mapsto(decimal \ form) = \boxed{4.6}  \\ \\  \ \ \ \ \ \ \ \ \ \ \\  \mapsto(mixed \ number \ form) = \boxed{ 4\frac{3}{5}}
____________________________________________________________

Question #2

\left[\begin{array}{ccc}  \left[\begin{array}{ccc}\boxed{\boxed{ 14\frac{1}{2} + 1\frac{1}{3} }}\end{array}\right] \end{array}\right] = \boxed{ \frac{19}{6}} \\ \\ \\
\mapsto (Decimal \ form)=(3.16) \\ \\ \mapsto (mixed \ number \ form) =  3\frac{1}{6}

I hope this helps you!
vredina [299]3 years ago
4 0
The answer to A is 4.6
The answer to B is 3.16
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Answer:

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Step-by-step explanation:

First we need to find the like terms so that we could add them. In this case the like terms are,

1. 6x , -2x , -10x

So, these are the only terms that we can add in this expression.

Hence,

=> 8x^{2} + 3 + (6x - 2x - 10x)

=> 8x^{2} + 3 + -6x

And this is as simple as this expression can go until we find the value of "x" which is not yet told.

Hope my answer helped.

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3 years ago
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Which value of x is in the solution 2|x-3|<4
Roman55 [17]

Answer:

1 < x < 5

Step-by-step explanation:

Inequalities of the type | x | < a , have solution of the form

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Given

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| x - 3 | < 2 , then

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8 0
3 years ago
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 270 day
dusya [7]

Answer:

a) 281 days.

b) 255 days

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 270, \sigma = 8

​(a) What is the minimum pregnancy length that can be in the top 8​% of pregnancy​ lengths?

100 - 8 = 92th percentile.

X when Z has a pvalue of 0.92. So X when Z = 1.405.

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 270}{8}

X - 270 = 1.405*8

X = 281

(b) What is the maximum pregnancy length that can be in the bottom 3​% of pregnancy​ lengths?

3rd percentile.

X when Z has a pvalue of 0.03. So X when Z = -1.88

Z = \frac{X - \mu}{\sigma}

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8 0
4 years ago
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DiKsa [7]

Answer:

The input value is 3/4

Step-by-step explanation:

we know that

The input value that produces the same output value for the two linear functions, is the intersection point both graphs

we have

f(x)=-3x+1 ---> equation A

g(x)=x-2 ---> equation B

Equate equation A and equation B

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3x+x=1+2

4x=3

x=\frac{3}{4}

therefore

The input value is 3/4

5 0
3 years ago
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