Make denomenators the same
common denom is 2n²
multiply 3/2n by n/n
mulitply 1/n² by 2/2
we get
combine fractions
multiply both sides by 2n²
2n+2=n-2
minus n both sides
n+2=-2
minus 2 both sides
n=-4
A) number of outcomes * number of outcomes =9*9=81
possible outcomes 123456789 for 1 digit
b)number of outcomes(even) * number of outcomes(even) =4*4=16
possible outcomes even 2468
Answer:
133 fishes
Step-by-step explanation:
Units of food A = 400 units
Units of food B = 400 units
Fish Bass required 2 units of A and 4 units of B.
Fish Trout requires 5 units of A and 2 units of B.
i. For food A,
total units of food A required = 2 + 5
= 7 units
number of bass and trout that would consume food A = 2 x 
= 114.3
number of bass and trout that would consume food A = 114
ii. For food B,
total units of food B required = 4 + 2
= 6 units
number of bass and trout that would consume food B = 2 x 
= 133.3
number of bass and trout that would consume food B = 133
Thus, the maximum number of fish that the lake can support is 133.
Answer:
1.555711807*10^10
Step-by-step explanation:
