Answer:
Average Atomic Mass = 10.81
Explanation:
Data Given:
Atomic Mass of ¹⁰X = 10 amu
Relative Intensity of ¹⁰X = 23 %
Atomic Mass of ¹¹X = 11 amu
Relative Intensity ¹¹X = 100 %
It means that if there are 123 atoms of this mystery element then then 23 will be of an isotope with atomic mass of 10 amu and the remaining 100 will be of an isotope with atomic mass of 11 amu.
So, we will now calculate the total mass of all elements as;
Total Mass = (23 × 10) + (100 × 11)
Total Mass = (230) + (1100)
Total Mass = 1330 amu
Then, we will calculate the average mass as,
Average Atomic Mass = 1330 / 123
Average Atomic Mass = 10.81
Well, the molar mass of acetone would be
3(12.011)+6(1.008)+15.999 , which cleans up to be 58.08 grams.
out of this total, 3(12.011), or 36.033 grams are carbon
So, to find the percent, you do part over whole
36.033/58.08, which equals 0.6204 with significant figures
multiply that by 100 to get 62.04%
Hope that helps!
Answer:
the answer that you are looking for is d
Explanation:
Answer:
The answer to your question is Cm = 2.093 J/kg°C
Explanation:
Data
mass metal = mass of water
Δ water = 5°
Δ metal = 10°
Cm = ?
Cw = 4.186 J/Kg°C
Formula
for metal for water
mCmΔTm = mCwΔTw
Cancel mass of metal
Cm ΔTm = CwΔTw
solve for Cm
Cm = (CwΔTw) / ΔTm
Substitution
Cm = (4.186 x 5) / 10
Simplification
Cm = 20.93 / 10
Result
Cm = 2.093 J/kg°C