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Maurinko [17]
3 years ago
14

What’s at the end of the leg bones?

Chemistry
1 answer:
Akimi4 [234]3 years ago
6 0

Answer:

Calfs

Explanation:

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The man is being warmed by?<br>radiation<br>convention<br>conduction<br>​
Lubov Fominskaja [6]

Answer:

Comvection

Explanation:

The movement causes the density to rise and therefore transfer more heat

6 0
3 years ago
(I ONLY HAVE 15 MIN LEFT IN MY TEST PLEASE HELP ME!!)
zloy xaker [14]

Answer:

183g

Explanation:

mass can't be created or destroyed so i think you just add up the total amounts of matter

8 0
3 years ago
Do you think crystals formed in conditions that were stable or did they change often?
andreev551 [17]

Answer:

They were made in unstable conditions

Explanation: Im smarty pants

6 0
3 years ago
Calculate the value of ΔG∘rxnΔGrxn∘ for the following reaction at 296 K. Ka = 2.9 × 10–8 and assume Ka does not change significa
oee [108]

Answer:

\Delta G_{rxn}=42.7\frac{kJ}{mol}

Explanation:

In this case, for the dissociation of hypochlorous acid, we know that the acid dissociation constant (Ka) is 2.9x10⁻⁸, which is related with the Gibbs free energy as shown below:

\Delta G_{rxn}=-RTln(K)

But in this case K is just Ka, therefore, at 296 K, it turns out:

\Delta G_{rxn}=-8.314\frac{J}{mol*K}*296K*ln(2.9x10^{-8})\\\\\Delta G_{rxn}=42.7\frac{kJ}{mol}

Such result, means that the reaction is nonspontaneous at the given temperature, it means it is not favorable (not easily occurring).

Best regards.

7 0
3 years ago
How much concentrated solution would it take to prepare 2.90 L of 0.420 M HCl upon dilution with water
Zanzabum

Answer:

the quantity required can go from 117 ml (for maximum concentration) up to 2900 ml ( if the concentrated solution has molarity =0.420 M)

Explanation:

the amount of water required to dilute a solution V₁ liters of Molarity M₁ to V₂ liters of M₂

moles of hydrochloric acid =  M₁ * V₁= M₂ * V₂

V₁ =   V₂ * M₂/M₁

where

M₂ = 0.420 M

V₂ =2.90 L

Since the hydrochloric acid can be concentrated up to 38% p/V  ( higher concentrations are possible but the evaporation rate is so high that handling and storage require extra precautions, like cooling and pressurisation)

maximum M₁ =38% p/V = 38 gr/ 0.1 L / 36.5 gr/mol = 10.41 M

then

min V₁ =   V₂ * M₂/ max M₁ =  2.90 L* 0.420 M/ 10.41 M= 0.117 L = 117 ml

then the quantity required can go from 117 ml up to 2900 ml ( if M₁ = M₂)

5 0
3 years ago
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